Answer:
y=ln(x/(1-x))
Step-by-step explanation:
y=e^x/(1+e^x)
Cross multiply
y(1+e^x)=e^x
Distribute
y+ye^x=e^x
Put anything with x on with side and everything without x on opposing side:
y=e^x-ye^x
Factor right hand side
y=(1-y)e^x
Divide both sides by (1-y)
y/(1-y)=e^x
Use natural log.
ln(y/(1-y))=x
The inverse is
y=ln(x/(1-x))
Answer: -7b² + 2b - 8
Step-by-step explanation:
<u>Given expression</u>
3 - b (7b + 2) + 3b - (11 - b)
<u>Expand parentheses and apply the distributive property if necessary</u>
=3 - b · 7b - b · 2 + 3b - 11 + b
=3 - 7b² - 2b + 3b - 11 + b
<u>Combine like terms</u>
=-7b² + (3b - 2b + b) + (3 - 11)
=
Hope this helps!! :)
Please let me know if you have any questions
Is that .9? or was that period mark accidental?
<span> -5a^2-19a^2-5a-8+12a^2-22-14a-2a
first gather all same powers
-5a</span>²-19a²+12a²-5a-14a-2a-8-22
-12a²-21a-30
-3(6a²+7a-+10)