All categories

3 years ago

What are the solutions to m2 – 9 = 0?

Mathematics

2 answers:

stiv31 [10]3 years ago

4 0

Answer:

m=-3

Step-by-step explanation:

m2-9=0

2 divied by 9 =3

when you have a positive number and a negitive number =a negitive

I think you get the point

STALIN [3.7K]3 years ago

4 0

Answer:

m = –3 and m = 3

Step-by-step explanation:

You might be interested in

331 students went on a field trip. Six buses were filled and 7 student traveled in cars. How many students were in buses.

lilavasa [31]

Yes because you subtract seven from 331 and that gives you 324 and you divide 324 divided by 6 and that gives you 54

3 0

3 years ago

I NEED HELP PLEASE, IM STUCK ON MOST OF THEM

azamat

Answer: look it up

Step-by-step explanation: Lollll

6 0

2 years ago

(6x-5y+4)dy+(y-2x-1)dx=0

Len [333]

(6x - 5y + 4) dy + (y - 2x - 1) dx = 0

(6x - 5y + 4) dy = (2x - y + 1) dx

dy/dx = (2x - y + 1) / (6x - 5y + 4)

Let X = x - a and Y = y - b. We want to find constants a and b such that

dY/dX = (a rational function)

where the numerator and denominator on the right side are free of constant terms. Substituting x and y in the equation, we have

dY/dX = (2 (X + a) - (Y + b) + 1) / (6 (X + a) - 5 (Y + b) + 4)

dY/dX = (2X - Y + 2a - b + 1) / (6X - 5Y + 6a - 5b + 4)

Then we solve for a and b in the system,

2a - b + 1 = 0

6a - 5b + 4 = 0

==> a = -1/4 and b = 1/2

With these constants, the equation reduces to

dY/dX = (2X - Y) / (6X - 5Y)

Now substitute Y = VX and dY/dX = X dV/dX + V :

X dV/dX + V = (2X - VX) / (6X - 5VX)

The equation becomes separable after some simplification:

X dV/dX + V = (2 - V) / (6 - 5V)

X dV/dX = (2 - V) / (6 - 5V) - V

X dV/dX = (2 - V - (6 - 5V)) / (6 - 5V)

X dV/dX = (4V - 4) / (6 - 5V)

- (5V - 6) / (4V - 4) dV = 1/X dX

Integrate both sides:

-5/4 V + 1/4 ln|4V - 4| = ln|X| + C

Extract a constant from the logarithm on the left:

-5/4 V + 1/4 (ln(4) + ln|V - 1|) = ln|X| + C

-5/4 V + 1/4 ln|V - 1| = ln|X| + C

-5V + ln|V - 1| = 4 ln|X| + C

Get this back in terms of Y :

-5Y/X + ln|Y/X - 1| = 4 ln|X| + C

Now get the solution in terms of y and x :

-5 (y - 1/2)/(x + 1/4) + ln|(y - 1/2)/(x + 1/4) - 1| = 4 ln|x + 1/4| + C

With some manipulation of constants and logarithms, and a bit of algebra, we can rewrite this solution as

-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|x + 1/4| + 4 ln(4) + C

-5 (4y - 2)/(4x + 1) + ln|(4y - 4x - 3)/(4x + 1)| = 4 ln|4x + 1| + C

-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| - ln|4x + 1| = 4 ln|4x + 1| + C

-5 (4y - 2)/(4x + 1) + ln|4y - 4x - 3| = 5 ln|4x + 1| + C

8 0

3 years ago

Sunny made 2 pitchers of strawberry smoothies for the science club. If each person got One-fifth of a pitcher, how many science

bagirrra123 [75]

Answer:

tell me what grade u are in and I will try my best to help

5 0

3 years ago

Read 2 more answers

1. Given the below sequence: -1, -3, -5, -7, . . . (a) What are the next 3 terms? (b) Is this an arithmetic or geometric sequenc

valentinak56 [21]

Answer:

(a) -7 , - 9 , - 11

(b) Arithmetic sequence

(d) -53

Step-by-step explanation:

(a) To find the next three terms , we must firs check if it is arithmetic sequence or a geometric sequence . For it to be an arithmetic sequence , there must be a common difference :

check :

-3 - (-1) = -5 - (-3) = -7 - (-5) = -2

This means that there is a common difference of -2 , which means it is an arithmetic sequence.

The next 3 terms we are to find are: 5th term , 6th term and 7th term.

$t_{5}$ = a + 4d

$t_{5}$ = - 1 + 4 ( -2 )

$t_{5}$ = -1 - 8

$t_{5}$ = - 9

6th term = a +5d

$t_{6}$ = -1 + 5(-2)

$t_{6}$ = -1 - 10

$t_{6}$ = - 11

$t_{7}$ = a + 6d

$t_{7}$ = -1 + 6 (-2)

$t_{7}$ = -1 - 12

$t_{7}$ = -13

Therefore : the next 3 terms are : -9 , -11 , - 13

(b) it is an arithmetic sequence because there is a common difference which is -2

(d) $t_{27}$ = a + 26d

$t_{27}$ = -1 + 26 ( -2 )

$t_{27}$ = -1 - 52

$t_{27}$ = - 53

5 0

3 years ago