Answer:
n = 15
Explanation:
Using
Given
Number of bytes = 32k
At the smallest scale in the computer, information is stored as bits and bytes.
In the cases when used to describe data storage bits/bytes are calculated as follows:
Number of bytes when n = 1 is 2¹ = 2 bytes
When n = 2, number of bytes = 2² = 4 bytes
n = 3, number of bytes = 2³ = 8 bytes
So, the general formula is
Number of bytes = 2^n
In this case
2^n = 32k
Note that 1k = 1024 bytes,
So, 32k = 32 * 1024 bytes
Thus, 2^n = 32 * 1024
2^n = 2^5 * 2^10
2^n = 2^15
n = 15.
Answer:
For a private computer investigation into cyber crime the private sector should complete all its courses and must be certified by the relevant authorities and must also be an expert in the computer investigations.
while
Public computer investigations has more aspects that involves non-certified personnel's
The private-sector computer investigations are used mostly on all the cyber crimes and hacking and loss of business data.while public-sector computer investigations are used on crimes like rapes, accidents and murders crimes
Explanation:
Computer forensics are used to resolve crimes like cyber crime, hacking, malfunctions and data interrupts.
Before a private computer investigations which is into cyber crime investigation can continue, the private sector should complete all its courses and must be certified by the relevant authorities and must also be an expert in the computer investigations.
while
Public computer investigations has more aspects that involves non-certified personnel's and the personnel's are not necessarily supposed to complete the courses
The private-sector computer investigations are used mostly on all the cyber crimes and hacking and loss of business data.while public-sector computer investigations are used on crimes like rapes, accidents and murders crimes
Answer:
MIPS Code:
.data
newline: .asciiz "\n" #newline variable
.text
MAINLOOP:
li $v0, 5 #syscall to get user interger and store in $v0
syscall
add $a0, $zero, $v0 #moving the user input to $a0 from $v0
beq $a0, 0, EXIT #branching to EXIT when $a0 is 0
li $v0, 1 #syscall to print integer in $a0
syscall
li $v0, 4 #syscall to print newline
la $a0, newline
syscall
j MAINLOOP #jumping to MAINLOOP
EXIT:
Sample Output:
6
6
7
7
3
3
0
Answer: NVRAM(Non-volatile random-access memory)
Explanation:Non-volatile random-access memory(NVRAM) is the memory that has a non-volatile nature.It is used for retaining of the data even when the system gets switched off .
This memory uses the power source from the CMOS battery for executing the functions. It is designed by using the pin configurations containing 24 pin in DIP(Dual inline package). So the situation mentioned in the question of storing the changes will appear in the NVRAM.
Answer:
I would 100% make myself a SmartToaster (Trademark Pending)
Explanation:
A simple explanation would be <em>I like toast</em>
