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arsen [322]
3 years ago
6

Oliver bought a scarf that costs 8 dollars and a watch that costs 9 dollars. At the counter he received a discount. If he paid o

nly 13 dollars, how many dollars was the discount.
Mathematics
1 answer:
Alex787 [66]3 years ago
7 0

Answer: 4

Step-by-step explanation:8 + 9 = 17 you take what he paid 13 and subtract 13 from 17 and you get 4. 4 is how many dollars off he got.

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Simplify 3/4(1/2x + 4) + 1/2(x − 1)
sergejj [24]

3/4(1/2x + 4) + 1/2(x − 1)

First use distributive property to remove the parentheses:

3/8x + 3 + 1/2x -1/2

Now combine like terms:

7/8x + 2 1/2

3 0
4 years ago
2x-1/2=3-x<br> solve for x.
DanielleElmas [232]
Given,

2x - 1/2 = 3 - x

2x + x = 3 + 1/2

3x = 7/2

3x = 3.5

x = 3.5/3

x = 1.167
8 0
3 years ago
FREE POINTS!!!!
algol13

Answer:

a ≈

2.594

b ≈

2.705

c ≈

2.718

d ≈

2.718

e ≈

2.718

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A researcher is interested in estimating the average salary of police officers in a large city. She wants to be 95% sure that he
inn [45]

Answer:

The sample size is 183.

Step-by-step explanation:

Given:

σ = $1050, ppulatin standard deviation

99% confidence interval

Accuracy = +/- $200

The accuracy is given by

z*(σ/√n)

where

z* = 2.576 for 99% confidence level (from tables)

n = sample size

Therefore

2.576(1050/√n) = 200

√n = (2.576*1050)/200 = 13.524

n = 182.9

<em>The sample size is 183</em>

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6 0
3 years ago
A machine is designed to fill 16-ounce bottles of shampoo. When the machine is working properly, the amount poured into the bott
Andreyy89

Answer:

(15.8495,16.2505)  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 16.05 ounces

Standard Deviation, σ = 0.2005 ounces

We are given that the distribution of amount poured into the bottles is a bell shaped distribution that is a normal distribution.

Empirical rule:

  • It states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ).
  1. It shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

Confidence interval:

\mu \pm 2\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

16.05 \pm 2(\frac{0.2005}{\sqrt{4}} ) = 16.05 \pm 0.2005 = (15.8495,16.2505)

4 0
3 years ago
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