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3 years ago

PLEASE HELP WORTH 100 points

Mathematics

1 answer:

enot [183]3 years ago

8 0

Answer:

He may have miscalculated the length of Path A

Step-by-step explanation:

I really hopes this helps

Have a great day!

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When 24 is subtracted from a number and that difference is multiplied by 1/4, the result is 4.

Katen [24]

If (x-24)0.25 = 4, distribute 0.25 within the parenthesis.
0.25x - 6 = 4
0.25x = 10
Divide both sides by 0.25
x = 40

8 0

3 years ago

WILL MARK BRAINLIEST!!!!!! 25 PTS

LuckyWell [14K]

Answer:

Step-by-step explanation:

SAS stands for side angle side. so in this question we know that one side is equal to another side, but we don't know wether or not there is another angle and another side that is congruent. so for that reason it is not congruent by SAS.

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3 years ago

2. Henry spends $90.00 on lunch and spends $16.00 on bananas. Hicks

Komok [63]

Answer:

it will cost him $226 and his left over amount will be 24 dollars.

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3 years ago

Can someone answer this please

lidiya [134]

Answer:

last one or d

Step-by-step explanation:

because she has less then 324

7 0

2 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

tangare [24]

Answer:

<h3>The given expression can be written in the form $q(x)+\frac{r(x)}{b(x)}$ as $(2x^2-x+3)+\frac{0}{x-3}$ where q(x)= $2x^2-x+3$ , r(x)=0 and b(x)=x-3</h3>

Step-by-step explanation:

Given rational expression is $\frac{2x^3-7x^2+6x-9}{x-3}$

<h3>To rewrite the given rational expression in the given form and match their correct expressions:</h3>

Rewrite the given rational expression $\frac{2x^3-7x^2+6x-9}{x-3}$ in the form of $q(x)+\frac{r(x)}{b(x)}$ where q(x) is the quotient, r(x) is the remainder and b(x) is the divisor.

<h3>Now solve the given expression by using Synthetic division, we get</h3>

Since x-3 is a factor for $2x^3-7x^2+6x-9$

<h3>Therefore b(x)=x-3</h3>

3_| 2 -7 6 -9

0 6 -3 9

------------------------------------

2 -1 3 0

------------------------------------

Therefore we have quadratic equation $2x^2-x+3=0$

<h3>q(x)= $2x^2-x+3$ </h3><h3>Remainder is 0</h3><h3>Therefore r(x)=0</h3>

Therefore we can write in the form as $(2x^2-x+3)+\frac{0}{x-3}$

It is in the form of $q(x)+\frac{r(x)}{b(x)}$

<h3>Therefore the given expression can be written in the form $q(x)+\frac{r(x)}{b(x)}$ as $(2x^2-x+3)+\frac{0}{x-3}$ where q(x)= $2x^2-x+3$ , r(x)=0 and b(x)=x-3</h3>

3 0

3 years ago

Read 2 more answers