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Nastasia [14]
3 years ago
10

Yall rachits and yall eat butt xD

Computers and Technology
2 answers:
Trava [24]3 years ago
6 0
Please use this for questions.
True [87]3 years ago
3 0

Answer:

I reported you.

Explanation:

because.

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In what year was the first world-wide web software created by tim berners-lee?
Elena L [17]
1989 <span>A graduate of Oxford University, Tim Berners-Lee invented the Web while at CERN, the European Particle Physics Laboratory, in </span>1989<span>. He wrote the first web client and server in </span>1990<span>.</span>
6 0
3 years ago
Array, destination contains the number of 10 cities numbered 1 to 10 that the products were shipped to. Hence, 10 quantities of
Naddik [55]

Answer:

#include <stdlib.h>

#include <stdio.h>

void func1(int product[]){

int orders[6]={0};

for(int i=0;i<70;i++){

orders[product[i]]++;

}

printf("Total number of each type of products that were bought\n");

for(int i=1;i<=5;i++){

printf("Product %d = %d\n",i,orders[i]);

}

}

void func2(int product[],int quantity[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

total_cost+= price[product[i]]* quantity[i];

}

printf("The total cost of all 70 orders = %.2f\n",total_cost);

}

void func3(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]==8){

total_cost+= price[product[i]]* quantity[i];

}

}

printf("The total cost of all products shipped to destination 8 = %.2f\n",total_cost);

}

void func4(int product[],int quantity[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders where each order is $50 or more = %d\n",total_orders);

}

void func5(int product[],int quantity[],int origination[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %d\n",total_orders);

}

void func6(int product[],int quantity[],int origination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]] * quantity[i]>=50){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %.2f\n",total_cost);

}

void func7(int origination[],int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_orders++;

}

}

printf("The total number of orders that originated from 3 and shipped to 8. = %d\n",total_orders);

}

void func8(int product[],int quantity[],int origination[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total cost of orders that originated from 3 and shipped to 8. = %.2f\n",total_cost);

}

void func9(int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_orders++;

}

}

printf("The total number of orders that was shipped to all destinations except to 8. = %d\n",total_orders);

}

void func10(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_cost += price[product[i]] * quantity[i];;

}

}

printf("The total cost of orders that was shipped to all destinations except to 8. = %.2f\n",total_cost);

}

int main(){

int product[70] = {4, 2, 4, 2, 4, 5, 5, 2, 2, 5, 5, 4, 3, 5, 4, 2, 5, 3, 1, 2, 2, 3, 3, 4, 5, 5, 4, 5, 3, 5, 5, 1, 4, 5, 1, 5, 3, 2, 4, 1, 2, 4, 5, 1, 5, 5, 5, 5, 5, 2, 5, 1, 4, 4, 4, 2, 3, 3, 3, 3, 4, 3, 5, 5, 3, 2, 3, 5, 3, 2};

int quantity[70] = {10, 9, 6, 4, 10, 4, 9, 6, 10, 7, 3, 4, 4, 9, 1, 8, 9, 1, 5, 8, 7, 2, 3, 4, 10, 5, 6, 2, 1, 7, 2, 8, 6, 9, 8, 8, 7, 7, 9, 10, 6, 7, 8, 2, 1, 7, 6, 3, 3, 1, 8, 4, 10, 7, 1, 10, 6, 9, 8, 2, 4, 6, 1, 8, 2, 6, 10, 2, 6, 2};

int origination[70] = {2, 7, 5, 5, 7, 2, 7, 2, 7, 7, 5, 2, 5, 5, 5, 2, 2, 7, 2, 7, 7, 2, 2, 2, 2, 5, 7, 5, 7, 7, 5, 5, 2, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 2, 7, 2, 7, 5, 2, 2, 2, 5, 7, 2, 5, 5, 5, 7, 7, 2, 5, 2, 7, 5, 2, 5, 7};

int destination[70] = {8, 7, 3, 10, 2, 6, 4, 5, 1, 3, 5, 9, 5, 8, 6, 4, 3, 7, 1, 2, 7, 2, 8, 2, 2, 1, 2, 6, 10, 2, 7, 7, 8, 6, 8, 8, 4, 8, 3, 10, 6, 9, 4, 9, 5, 1, 7, 3, 1, 7, 5, 5, 4, 9, 3, 10, 8, 1, 1, 1, 1, 8, 10, 3, 5, 2, 8, 7, 4, 10};

float price[6]={0,11.95,7.95,19.95,24.95,15.25};

func1(product);

func2(product,quantity,price);

func3(product,quantity,destination,price);

func4(product,quantity,price);

func5(product,quantity,origination,price);

func6(product,quantity,origination,price);

func7(origination,destination);

func8(product,quantity,origination,destination,price);

func9(destination);

func10(product,quantity,destination,price);

}

Explanation:

The program inputs order, products and cities products are shipped.

After a series of conditional requirements being met, will output the destination each product os going to and the number of products with its associated price.

3 0
4 years ago
Read 2 more answers
Write a program in Java programming language that given two clock times prints out the absolute number of minutes between them
Triss [41]

Answer:

// Java Program to Find the difference

// between Two Time Periods

// Importing the Date Class from the util package

import java.util.*;

// Importing the SimpleDateFormat

// Class from the text package

import java.text.*;

public class GFG {

public static void main(String[] args) throws Exception

{

 // Dates to be parsed

 String time1 = "18:00:00";

 String time2 = "7:30:50";

 // Creating a SimpleDateFormat object

 // to parse time in the format HH:MM:SS

 SimpleDateFormat simpleDateFormat

  = new SimpleDateFormat("HH:mm:ss");

 // Parsing the Time Period

 Date date1 = simpleDateFormat.parse(time1);

 Date date2 = simpleDateFormat.parse(time2);

 // Calculating the difference in milliseconds

 long differenceInMilliSeconds

  = Math.abs(date2.getTime() - date1.getTime());

 // Calculating the difference in Hours

 long differenceInHours

  = (differenceInMilliSeconds / (60 * 60 * 1000))

  % 24;

 // Calculating the difference in Minutes

 long differenceInMinutes

  = (differenceInMilliSeconds / (60 * 1000)) % 60;

 // Calculating the difference in Seconds

 long differenceInSeconds

  = (differenceInMilliSeconds / 1000) % 60;

 // Printing the answer

 System.out.println(

  "Difference is " + differenceInHours + " hours "

  + differenceInMinutes + " minutes "

  + differenceInSeconds + " Seconds. ");

}

}

7 0
2 years ago
Plzzzzz help me with this and be serious dont comment random things
RoseWind [281]

Answer:

legal and ethical questions

brick and mortar guidelines

website content

customer information

the facts of life

payment processing

human resources

this is in career explorations 2 please help will mark the brainiest ​

Explanation: yes he is right this is correct

7 0
3 years ago
Write a function that takes a character string value and prints out the bytes stored in memory of its representation (including
Goryan [66]

Answer:

C++ code explained below

Explanation:

SOURCE CODE:

*Please follow the comments to better understand the code.

#include <stdio.h>

int numOfBytes(char* string)

{

// initialise the variables

int i=0,size=0;

// while the string reaches to \0, repeat the loop.

while(string[i]!='\0')

{

// add that size

size += sizeof(*string);

 

// increase the i value.

i++;

}

// add 1 byte for \0

size = size+1;

return size;

}

int main() {

char name[]="Praveen Kumar Reddy";

printf("The size is %d bytes.",numOfBytes(name));

 

  return 0;

}

=============

6 0
3 years ago
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