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Marta_Voda [28]
3 years ago
15

What’s the answer to -40 = 8(g-11)

Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0
-40= 8g-88
+88
48=8g
G=6
Serhud [2]3 years ago
4 0

Answer:

g = 6

Step-by-step explanation:

- 40 = 8 ( g - 11 )

- 40 = 8g - 88

+88 .        +88

48 = 8g

__ .   ___

8 .      8

6 = g  

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How much does a customer pay for an article marked at $50 if a sales tax of 6% is charged?
Brrunno [24]

Answer:

53$

Step-by-step explanation:

6% of 50 is 3, 50+3=53

6 0
3 years ago
What is the most common factor between 139 and 100
posledela

Answer:

1

Step-by-step explanation:

The common factors are:

1

The Greatest Common Factor:

GCF = 1

Solution

Teh factors of 100 are:

1, 2, 4, 5, 10, 20, 25, 50, 100

Teh factors of 139 are:

1, 139

The common factors are:

1

The Greatest Common Factor:

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3 0
3 years ago
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Each of 5 birdwatchers reported seeing 15 roseate spoonbills in a day. If they each reported seeing the same nunber of roseate s
LuckyWell [14K]
Each of the 5 saw 15 birds a day, so they saw 75 each day for 14 days. 75 times 14 is 1,050. They saw in total, 1,050 birds.
4 0
4 years ago
Find a point on the ellipsoid x2+y2+4z2=36x2+y2+4z2=36 where the tangent plane is perpendicular to the line with parametric equa
Anvisha [2.4K]

Answer:

A point on the ellipsoid is (-4,2,2) or (4,-2,-2)

Step-by-step explanation:

Given equation of ellipsoid f(x,y,z) :x^2+y^2+4z^2=36

Parametric equations:

x=-4t-1

y=2t+1

z=8t+3

Finding the gradient of function

\nabla f(x,y,z)=\\\nabla f(x,y,z)=

So, The directions vectors=(-4,2,8)

Now the line is perpendicular to plane when direction vector is parallel to the normal vector of line

\nablaf(x,y,z)=(2x,2y,8z)=\lambda(-4,2,8)

So, 2x=-4\lambda

\Rightarrow x=-2\lambda

2y=2\lambda\\\Rightarrow y=\lambda\\8z=8\lambda\\\Rightarrow z=\lambda

Substitute the value of x , y and z in the ellipsoid equation

(2\lambda)^2+(\lambda)^2+4(\lambda)^2=36\\9(\lambda)^2=36\\\lambda^2=4\\\lambda=\pm 2

With \lambda = 2

x=-2(2)=-4

y=2

z=2

With\lambda =- 2

x=-2(-2)=4

y=-2

z=-2

Hence a point on the ellipsoid is (-4,2,2) or (4,-2,-2)

7 0
3 years ago
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kolezko [41]
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I wish I made that much.
3 0
4 years ago
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