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3 years ago

10

The instructions for building a kite tell you to begin by cutting a strip of wood to 45 cm in length, but your ruler only measur

es inches. How many inches should the piece of wood be? Round to the nearest quarter of an inch. (Recall: 1 in.= 2.54cm )

1 answer:

Shalnov [3]3 years ago

3 0

i think its 11.45 rounded its 11.5 from what I found its this

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A laboratory technician needs to make a 81-liter batch of a 20% acid solution. How can the laboratory technician combine a bat

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3 years ago

25 POINTS AVAILABLE

myrzilka [38]

Answer:

$\large\boxed{1.\ (-3, 0),\ r = 3}\\\boxed{2.\ (x+4)^2+(y-3)^2=36}\\\boxed{3.\ (x-2)^2+(y-1)^2=(\sqrt{34})^2}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

1. We have the equation:

$(x+3)^2+y^2=9\\\\(x-(-3))^2+(y-0)^2=3^2$

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2. We have the center (-4, 3) and the radius r = 6. Substitute:

$(x-(-4))^2+(y-3)^2=6^2\\\\(x+4)^2+(y-3)^2=36$

3. We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

7 0

3 years ago

A circle is centered at (5, 4) and has radius 6. Write its equation in standard form.

dimulka [17.4K]

A circle equation is (x – h)^2<span> + (y – k)^</span>2<span> = r^</span><span>2 where (h,k) is the center and r is the radius. Now all we have to do is plug in the variables.

Since (h,k)=(5,4) and r= 6

The answer would be C.

Your welcome ;)

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8 0

3 years ago