Answer:
![\log_{2} [\frac{x^{3}(x + 4)}{3}]](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%20%5B%5Cfrac%7Bx%5E%7B3%7D%28x%20%2B%204%29%7D%7B3%7D%5D)
Step-by-step explanation:
We have to write the following logarithmic expression as a single logarithm.
The given expression is
![3\log_{2} x - [\log_{2} 3 - \log_{2}(x + 4)]](https://tex.z-dn.net/?f=3%5Clog_%7B2%7D%20x%20-%20%5B%5Clog_%7B2%7D%203%20-%20%5Clog_%7B2%7D%28x%20%2B%204%29%5D)
= 
{Since, 
, from the properties of logarithmic function }
= 
{Since, 
, which also a logarithmic property}
= ![\log_{2} [\frac{x^{3}}{\frac{3}{x + 4}}]](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%20%5B%5Cfrac%7Bx%5E%7B3%7D%7D%7B%5Cfrac%7B3%7D%7Bx%20%2B%204%7D%7D%5D)
= (Answer)
Answer:
184
Step-by-step explanation:
The sqrt(144) = 12
14^2 = 196
196 - 12 - 184
In the given you wrote -2, whereas it should be -2i
z = a + bi and in trigo form | z |.(cos Ф + i.sin Ф).
z = 0 -2i → | z |.(cos Ф + i.sin Ф)
Now let's calculate z:
z² = a²+b² → z² = 0² (-2.i)² → z = -2(i)² →z= -2(-1) → z = |2|
tan Ф = b/a = -2/0 → tan Ф → - ∞ ↔ Ф = -90° or Ф = 270°
then the - 2 I ↔ |2|(cos 270° + i.sin 270°)
Answer:
4. x= 18
Step-by-step explanation:
We solve the problem like this:
Since 3 is proportional to 6 and 9 is proportional to x, we set up a proportion.
3/9 = 6/x
We then use cross-multiplication to solve for x.
