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Rus_ich [418]
3 years ago
13

Lila flies a drone in the direction of 90° towards Avery. Once she gets to Avery she changes course and flies in the direction o

f 200° towards Mark. Lila and Avery are 20 feet apart; Mark and Avery are 30 feet apart. How far apart are Mark and Lila?
Mathematics
1 answer:
Nikitich [7]3 years ago
8 0

Answer:

X = 13.13 feet

Step-by-step explanation:

Let the distance between Lila and Mark be x.

Let the distance between Avery and lila be A= 20

Let the distance between Avery and Mark be B= 30

Angle x = 200-180=20°

To solve this question we will use the cosine formula which is

X² = A²+ B² -2ABcosx

X²= 20² + 30² -2(20)(30)cos20

X²=1300-1127.6

X²= 172.4

X= 13.13

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The coordinates of B and D are the location of the vertices B and D in the rectangle

The coordinates of B and D are (55, 30) and (55, 14)

<h3>How to determine the coordinates of B and D?</h3>

From the figure of the rectangle, we have:

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C = (40, 22)

Point B has the same y-coordinate as point A

So, we have:

B = (x, 30)

The x-coordinate is then calculated as:

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Point D has the same x-coordinate as point B

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D = (55, y)

The y-coordinate is then calculated as:

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So, the coordinates of B are:

D = (55, 14)

Hence, the coordinates of B and D are (55, 30) and (55, 14)

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brainly.com/question/10737082

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2 years ago
Claire wants to start a stamp collection. She spends $15 on an album to hold her stamps and $1.25 for each stamp. If she has $40
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The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature
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The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

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T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}

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(t) = \ time

T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)

T_{s} = Surrounding \ temperature

T_{0} = Initial \ temperature \ of \ the \ body

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From the question,

T_{0} = 86 ^{o}C

T_{s} = -20 ^{o}C

∴ T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C

T_{0} - T_{s} = 106^{o} C

Therefore, the equation T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt} becomes

T_{(t)}=-20+106 e^{kt}

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After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

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Then, we get

58 = -20+106 e^{k(1)}

Now, solve for k

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