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NeX [460]
3 years ago
13

Write an equation for the nth term of the given geometric sequence -12,-36,-108...an

Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

nth term of the geometric sequence

an= -12*3^(n-1)

Step-by-step explanation:

First term

a= -12

Second term

ar= -36

-12r=-36

r=-36/-12

=3

Third term

ar^2= -108

-12(3)^2

= -12(9)

= -108

nth term of the geometric sequence

an=ar^(n-1)

= -12*3^(n-1)

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The answer is the first data set because remember, an outlier is a number in a data set that is extremely far away from all of the other numbers.

You can easily tell which one is the outlier, the first data set's outlier is 13, because it is was placed so far away from the other data points.

We know that the first data set is correct because all of the other data sets have numbers that are clustered together.

~Hope I helped!~
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3 years ago
Need help with this question
Amiraneli [1.4K]

Answer:

1 and 3, 2 and 4

Step-by-step explanation:

Supplementary angles total to 180° or should form a straight line. 1 and 3, 2 and 4 are vertical angles which equal one another and are not supplementary.

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3 years ago
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galben [10]

Answer:

∛27 = 3

Step-by-step explanation:

A radical is simply a fractional exponent: a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }

Hence, ∛27 = 27^{(\frac{1}{3})}

Since 27 = 3³, then:

You could rewrite ∛27 as ∛(3)³.

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Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the <u><em>multiplicative inverse</em></u> of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.

Therefore, ∛27 = 3.

3 0
3 years ago
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34kurt
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Answer:

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