Kingdom Monera was the oldest kingdom of living organisms. The organisms in the kingdom were simple, single celled and their cellular organelles were not covered by membranes. Prokaryotic bacteria were the first known Monerans. However, scientists think that Monerans were evolved into more complex eukaryotic organisms (Protists) with the passage of time.
But how did Monera (Prokaryotes) was evolved into Protista (Eukaryotes)?
Protista are eukaryotes, unicellular or simple multicellular organisms.Many theories were proposed for this evolution, but one that makes most sense was endosymbiotic theory. According to this, the first eukaryotic cells were evolved when two prokaryotic cells existed in an endo-symbiotic relationship. Larger prokaryotic cells engulfed smaller prokaryotic cells. The smaller cells got shelter and nutrients from larger cells and both co-existed in a mutualistic relationship. Both cells eventually evolved into organelles and got never aparted. This is how more complex organisms’ protists were evolved from simple monerans. It was a gradual process and took millions of years.
The earliest fungi were single-celled organisms that contain a flagella to move from one place to another. Recent studies indicate that fungi belong to a group of organisms which were evolved from protists over the course of time. These studies are based on the nucleotide sequence of fungi that matches to a large extent with old protists. It is estimates that fungi evolved 600 million years or even before.
I may be wrong but i think it is B. <span>call 9-1-1 or the local emergency number quickly, then return to give care to the child.
I hope this is right</span>
<em>Answer</em>
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<em>Clastic sedimentary rocks are made up of pieces of pre-existing rocks. Pieces of rock are loosened by weathering, then transported to some basin or depression where sediment is trapped. If the sediment is buried deeply, it becomes compacted and cemented, forming sedimentary rock</em>
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<em>Hope this help's you</em>
The nitrogen containing amino group is recycled while the remainder of the molecule is excreted in the urine
Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.