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3 years ago

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Evaluate 8(7x--3) when x=9

1 answer:

Schach [20]3 years ago

5 0

I will assume that by "Evaluate 8(7x--3) when x=9" you meant:

"Evaluate 8(7x-3) when x=9."

First, substitute 9 for x in 7x-3: 7(9)-3 = 60. Rewrite the problem as:

8(60). Multiply. Answer: 480

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4 years ago

10 < 0.25 ( x + 1 ) < 11

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10 <0.25 (x + 1) <11
We must solve two inequalities in this case.
Inequality 1:
10 <0.25 (x + 1)
10 / 0.25 <x + 1
40 <x + 1
40-1 <x
39 <x
Inequality 2:
0.25 (x + 1) <11
(x + 1) <11 / 0.25
(x + 1) <44
x <44-1
x <43
The final result is:
39 <x <43
Answer:
39 <x <43

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