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iren2701 [21]
3 years ago
10

Evaluate 8(7x--3) when x=9

Mathematics
1 answer:
Schach [20]3 years ago
5 0

I will assume that by "Evaluate 8(7x--3) when x=9" you meant:

"Evaluate 8(7x-3) when x=9."

First, substitute 9 for x in 7x-3: 7(9)-3 = 60. Rewrite the problem as:

8(60). Multiply. Answer: 480

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Write the equation of line that passes through (-1,3) and (-5,-3)
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Answer:

y =  \frac{3}{2} x + 4 \frac{1}{2}

Step-by-step explanation:

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gradient \: of \: line \\  =  \frac{3 - ( - 3)}{ - 1 - ( - 5)}  \\  =  \frac{3 + 3}{5 - 1}  \\  =  \frac{6}{4}  \\  =  \frac{3}{2}

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Now, find the value of c by substituting a coordinate into the above equation.

when x=-1, y=3,

3 =  \frac{3}{2} ( - 1) + c \\ 3 =  -\frac{3}{2}  + c \\ c = 3 +  \frac{3}{2}  \\ c = 4 \frac{1}{2}

Therefore the equation of the line is

y =  \frac{3}{2} x +  4\frac{1}{2}

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