For this case we have that by definition:

So:

We apply distributive property that states that:

In addition, we take into account that:


Answer:

Option B
Answer:
55
Step-by-step explanation:
Let x represent the middle integer. Then the smallest is x-2 and the largest is x+2. Your requirement is that ...
(x-2)/(x+2) > 2/3
3x -6 > 2x +4 . . . . cross multiply
x > 10 . . . . . . . . . . .add 6-2x
The smallest integer satisfying this requirement is x=11. The sum of the 5 integers is 5x = 55.
The smallest sum is 55.
Answer:
I think the answer is

Step-by-step explanation:
Reason :

Therefore

Answer:
9/22
Step-by-step explanation:
First:
Convert any mixed numbers to fractions.
Then your initial equation becomes:
−9/4 ÷ −11/2
Applying the fractions formula for division,
=−9×2 divided by 4×−11
=−18/−44
Simplifying -18/-44, the answer is
=9/22
D. 192in^2
This would be a simple area problem with a triangle. REMEMBER THIS EQUATION: a=bh*1/2 (b for base and h for height, these are multiplied together then that answer is halved out.)
So we just need to plug in our values into the equation, so the equation would look like a= (16)*(24)*1/2. 16 times 24 would then give you 384, you could either divide by 2 or multiply by 0.5 to get the next answer, as long as your HALVING the answer.
So we have our bh value so now we can multiply by 1/2 which will give us 384*1/2 which leaves us with 192.
I have also attached a photo of doing a longer(ish) way than this, that also proves that this equation works. Either one will provide you an answer.