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lys-0071 [83]
3 years ago
6

For similar light intensity, compact fluorescent bulbs use about 25% of the energy of incandescent bulbs. Let's say you replaced

a bulb of 100 W with a fluorescent bulb and that your utility charges $0.15/kW-hour. How many dollars would you save in electricity in the 10,000−hour lifetime of the bulb?

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

$112.50¢

Step-by-step explanation:

please kindly check the attached file for explanation

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A table with a round top is cut in half so that it can be used against a wall. After it is cut, the edge along the wall is 6 fee
andrew-mc [135]
The diameter is 6 feet, so the radius is 3 feet.  
The formula to solve for the areas of a circle is 
A = πr^2
So, A = (3.14)(3^2)
A = 28.26
Since the table is cut in half, divide the total answer by 2
A = 14.13
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Zoe has 8 cups of whole-wheat flous. If each loaf of her favourite graad requires 3/4 of a cup of whole wheat flour, how many wh
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No. of cups = 8 cups
@ loaf = 3/4

No of loaves she can make 

8 cups ÷ 0.75 = 10.67

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3 years ago
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Witch answer choice represents a person running 90 calories by climbing 18 flights of stairs
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Where are the answer choices?
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2 years ago
Simplify the expression−6v + 3v
Maurinko [17]

Answer:

-3v

Step-by-step explanation:

-6v is a negative when 3v is positive

when you add 3v to -6v it equals -3v since 6 is greater

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3 years ago
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Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate
Leviafan [203]

Answer:

Probability of having student's score between 505 and 515 is 0.36

Given that z-scores are rounded to two decimals using Standard Normal Distribution Table

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu (Mean) = 510, SD = 10.4 we have z(x) by using z(x) = (x - Mu)/SD as under:

In our case, we have x = 505 & 515

Approach 1 using Standard Normal Distribution Table:

z for x=505: z(505) = (505-510)/10.4 gives us z(505) = -0.48

z for x=515: z(515) = (515-510)/10.4 gives us z(515) = 0.48

Afterwards using Normal Distribution Tables and rounding the values to two decimals we find the probabilities as under:

P(505) using z(505) = 0.32

Similarly we have:

P(515) using z(515) = 0.68

Now we may find the probability of student's score between 505 and 515 using:

P(505 < x < 515) = P(515)-P(505) = 0.68 - 0.32 = 0.36

PS: The standard normal distribution table is being attached for reference.

Approach 2 using Excel or Google Sheets:

P(x) = norm.dist(x,Mean,SD,Commutative)

P(505) = norm.dist(505,510,10.4,1)

P(515) = norm.dist(515,510,10.4,1)

Probability of student's score between 505 and 515= P(515) - P(505) = 0.36

Download pdf
6 0
3 years ago
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