Perimeter of the equilateral triangle KLM with vertices K(-2 ,1) and M (10,6) is equal to 39 units.
As given in the question,
Coordinates of vertices K(-2,1) and M(10,6)
KM =
=
= 13units
In equilateral triangle KL = LM = KM = 13 units
Perimeter of equilateral triangle KLM = 13 +13 +13
= 39 units
Therefore, perimeter of the equilateral triangle KLM with vertices K(-2 ,1) and M (10,6) is equal to 39 units.
Learn more about perimeter here
#SPJ4
Answer:
(For the first two questions I do believe that you will need a protractor to calculate the angles.)
15) measures out to -70° in order to display that the angle would be in quadrant IV (the bottom right quadrant.)
The first image attached shows where the angle should be located.
16) is equal to 60° (the line you draw will be in quadrant 1 (the top right quadrant))
17) 350° is or 6.11 (the answer depends on the format the professor wants.)
18) 240° is radians or -4.19 (I am rounding to the nearest hundredths place the unsimplified answer is −4.18879020...)
Answer:
see explanation
Step-by-step explanation:
let y = f(x), then
y = 11x - 1
Interchange x and y and solve for y
x = 11y - 1 ( add 1 to both sides )
x + 1 = 11y ( divide both sides by 11 )
y = , hence
(x) =
