The answer too the problem is C
Since a calculator is involved in finding the answer, it makes sense to me to use a calculator capable of adding vectors.
The airplane's ground speed is 158 mph, and its heading is 205.3°.
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A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.
The ground speed and course of the plane are 158 mph @ 205.3°.
Answer:
The unit rate of $10 per hour.
Step-by-step explanation:
Given



See attachment for graph
Required
What does the given point represents
From the attachment, the origin of the graph is:

and we have the given point to be:
Calculate the slope (m)




The slope represents $10/1 hour
Hence:
means the unit rate is $10 per hour
A three-letter word used to show division in a word problem is PER.
Answer: Multiplying 3x and -x we obtain A= -3x^2