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Nostrana [21]
3 years ago
14

one of the solution to this problem below is 8. what is the other solution? C^2-64=0 ( please show your work )

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0
{c}^{2} - 64 = 0
This can also be represented as:
{c}^{2} - {8}^{2} = 0
Using difference of two squares;
(c - 8)(c + 8) = 0
c - 8 = 0 \: or \: c + 8 = 0 \\ \\ c = 8 \: or \: c = - 8



Hope I helped? ☺️
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Answer:

Th Range is [0, -∞)

Step-by-step explanation:

f(x) = 2 - x

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(f*w)(x)=(2-x)(x-2)\\=2x-4-x^2+2x\\=-x^2+4x-4

This is a quadratic function (U shaped), or a parabola. The graph is attached.

The range is the set of y-values for which the function is defined.

We see from the graph that the parabola is upside down and the highest value is y = 0 and lowest goes towards negative infinity. So the range is from 0 to negative infinity. Or,

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In interval notation, that would be:

[0, -∞)

4 0
3 years ago
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scoray [572]

Answer:

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Given

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elena-14-01-66 [18.8K]

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we know that

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using a graphing tool

The solution is the interval [6.78,39.22]

see the attached figure

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A reasonable constraint for the model is

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4 0
3 years ago
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Step-by-step explanation:

Do the parentheses first!

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