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shusha [124]
2 years ago
7

Three consecutive integers have a sum of 30. Which equation can be used to find x, the value of the smallest of the three number

s?
Mathematics
1 answer:
Katen [24]2 years ago
8 0

Answer:

The smallest value of the three numbers would be 9.

Step-by-step explanation:

In order to find this, set the smallest number as x. Then you can set each of the next integers as x + 1 and x + 2. Now we can total all three numbers and set equal to 30 to solve for x.

x + x + 1 + x + 2 = 30

3x + 3 = 30

3x = 27

x = 9

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b & d

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Two or more complete sentences, explain how to use ordered pairs of points in f(x) and g(x) to determine if f(x) and g(x) are in
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3 years ago
Please help 50 points!<br> Simplify the expressed
LenKa [72]

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Step-by-step explanation:

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\frac{x(x+3)-4(x+3)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}  , difference of 2 squares and perfect square

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3 0
2 years ago
5x^2-2x=2<br>help plsmmm​
Yuki888 [10]

Answer:

Presumably you're solving for x here?  Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\

let's solve it.  First we'll multiply both sides by five, making the first term a perfect square:

25x^2 - 10x - 10 = 0\\

Now we'll add 11 to both sides:

25x^2 - 10x + 1 = 11\\

Which makes the left side a perfect square:

(5x - 1)^2 = 11

And now we can solve for x:

(5x - 1)^2 = 11\\\\5x - 1 =  \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86             x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46

7 0
2 years ago
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