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AnnZ [28]
3 years ago
12

What is a horizontal asymptote of the function below?

Mathematics
1 answer:
xenn [34]3 years ago
3 0

Answer:

A. y = \frac{3}{4}

Step-by-step explanation:

For horizontal asymptote, if the degree of numerator is equal to the degree of the denomenator, then we take the ratio of cofficient of highest degree variable

f(x) = \frac{6}{8}

      = \frac{3}{4}

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Please help me with these questions​
Nonamiya [84]

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9) u= -12

11) -18 over 2

Step-by-step explanation:

Hope this helps!!

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3 years ago
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Express 20 cm to 400 mm in simplest form
solong [7]

Answer:

Step-by-step explanation:

36/24 or 3/2

4 0
3 years ago
Tina constructed triangle XYZ.
Oxana [17]

Answer:

It's D... Isosceles and right

Step-by-step explanation:

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7 0
3 years ago
The Insurance Institute for Highway Safety publishes data on the total damage caused by compact automobiles in a series of contr
erastova [34]

Answer: Min : $750\ ,\ Q_1= \$800\ ,\ Median : \$925\ ,\ Q_3=\$1050\ ,\ Max: \$1100

Step-by-step explanation:

The five -number summary consists of five values :

Minimum value , First quartile (Q_1) , Median , Third Quartile (Q_3)  , Maximum value.

Given : The Insurance Institute for Highway Safety publishes data on the total damage caused by compact automobiles in a series of controlled, low-speed collisions.

The following costs are for a sample of six cars:

$800, $750, $900, $950, $1100, $1050.

Arrange data in increasing order :

$750,$800, $900, $950, $1050, $1100

Minimum value =  $750

Maximum value = $1100

Median = middle most term

Since , total observation is 6 (even) , so Median = Mean of two middle most values ($900 and  $950).

i.e.  Median=\dfrac{900+950}{2}=\$925

First quartile (Q_1) = Median of lower half ($750,$800, $900)

= $800

, Third Quartile (Q_3)  = Median of upper half ($950,  $1050, $1100)

= $1050

Hence, the five-number summary of the total damage suffered for this sample of cars will be :

Min : $750\ ,\ Q_1= \$800\ ,\ Median : \$925\ ,\ Q_3=\$1050\ ,\ Max: \$1100

3 0
3 years ago
How do you solve this: 2y^2=x+4
marishachu [46]

To solve this for an equation that you can graph, you need to isolate the y variable. In order to do this, follow the order of operations for solving equation to get the equation.

2y^2 = x + 4 ----> divide both sides by 2

y^2 = \frac{x + 4}{2} ----> take the square root of both sides

y = \sqrt{\frac{x+ 4}{2}}

Now you have the equation solved for the y variable and can graph it.

5 0
3 years ago
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