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Stels [109]
2 years ago
11

In the context of relationship between variables, increases in the values of one variable are accompanied by increases in the va

lues of the second variable in a _____ relationship.
A. positive linear
B. non-linear
C. negative linear
D. curvilinear
Mathematics
1 answer:
garik1379 [7]2 years ago
7 0

Answer:

A. Positive linear.

Step-by-step explanation:

We have that both variables increases, then we have a positive relation. A curvilinear option can not be possible because with this option in some regions could happen that when one variable increases the other one decreases. The negative linear relation can no be because with this option when one variable increases the other decreases. A non linear option is the same as a curvilinear option then can not be possible. Then the best option is a positive linear relationship.

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Reggie lost 2 spaceships in level 3 of a video game. He lost 30 points for each spaceship. When he completed level 3, he earned
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Answer:

Increased by 290

Step-by-step explanation:

2(-30) = -60

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Now suppose instead that Jane withdraws $500 from her checking account and uses $300 of this money to pay her federal income tax
zysi [14]

Answer:

Step-by-step explanation:

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5 0
3 years ago
Why is this wrong?<br> What is the rigth answer?
pantera1 [17]
For every 7 votes for candidate a, there are 4 votes for candidate c
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3 years ago
Total profit P is the difference between total revenue R and total cost C. Given the following​ total-revenue and​ total-cost fu
gavmur [86]

Answer:

The profit function is:

P(x)=-x^2+1280x-3300

The maximum value is 406, 300 occurring when x = 640.

Step-by-step explanation:

The revenue function is:

R(x)=1300x-x^2

And the cost function is:

C(x)=3300+20x

Then the total profit function will be:

P(x)=R(x)-C(x)=(1300x-x^2)-(3300+20x)=-x^2+1280x-3300

This is a quadratic function.

Therefore, the maximum value of the total profit will occur at its vertex point.

The vertex of a quadratic is given by:

\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)

In this case, a = -1, b = 1280, and c = -3300.

Then the point at which the maximum profit occurs is at:

\displaystyle x=-\frac{1280}{2(-1)}=640

And the maximum profit will be:

P(640)=-(640)^2+1280(640)-3300=406300

5 0
3 years ago
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