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Snowcat [4.5K]
3 years ago
13

The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and

a standard deviation of 9.2 gigagrams per year. Find the probability that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 12.8 gigagrams and 14.0 gigagrams per year.
0.052
0.548
0.452
0.519
Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer: 0.052

Step-by-step explanation:

Given : The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and a standard deviation of 9.2 gigagrams per year.

i.e. \mu=13.9  and \sigma=9.2

Let x denotes the yearly amounts of carbon emissions from cars in Belgium.

Then, the probability that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 12.8 gigagrams and 14.0 gigagrams per year will be :-

P(12.8

Hence, the required probability = 0.052

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Step-by-step explanation:

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qaws [65]
Ok, I shall help.
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So first step
25x+8+9x+2=180
We can do this because they are interior angles which add to 180 degrees.
So now we simplify.
25x+9x+2+8=180
34x+10=180
Minus 10 from both sides to get x.
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Divide by 34 to only find x.
This leaves x=5 now we find y.
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We can make these two equal because they are alternate angles which are always equal.
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Now we minus 5 from both sides to leave 7y
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