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dmitriy555 [2]
3 years ago
6

.............................

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
4 0
It's B and C
hope this helps
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Evaluate 2(x+ 1 - 3 when x = 6 O Ο Α. 11 OB. 5 O C. 8 ( D. 10
Mashutka [201]

\implies {\blue {\boxed {\boxed {\purple {\sf {A. \:11}}}}}}

\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

2 \: ( \: x + 1 \: ) - 3

Plugging in the value "x\:=\:6" in the above expression, we have

= 2 \: ( \: 6 + 1 \: ) - 3

= 2 \: ( \: 7 \: ) - 3

= 14 - 3

= 11

<h3><u>Note</u>:-</h3>

\sf\red{PEMDAS\: rule.}

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

5 0
3 years ago
What is 5/7*w=40 1/2
sukhopar [10]

Answer:

56 7/10

Step-by-step explanation:

convert 40 1/2 to a fraction 40 1/2 = 81/2

multiply both sides by  7/5

this gets w by itself on the left

81/2 x 7/5 = 567/10 = 56 7/10

7 0
3 years ago
Solve for U <br><br> 11=8+u/7.68
BlackZzzverrR [31]

\begin{gathered}\\ \sf\longmapsto 11=\frac{8+u}{7.68}\end{gathered}

\begin{gathered}\\ \sf\longmapsto 11 =  \frac{8 + u}{ \frac{192}{25} } \end{gathered}

\begin{gathered}\\ \sf\longmapsto 11=\frac{(8+u)×25}{192}\end{gathered}

\begin{gathered}\\ \sf\longmapsto 11=\frac{200+25u}{192}\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2112=200+25u\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2112-25u=200\end{gathered}

\begin{gathered}\\ \sf\longmapsto -25u=200-2112\end{gathered}

\begin{gathered}\\ \sf\longmapsto -25u=-1912\end{gathered}

\begin{gathered}\\ \sf\longmapsto u=\frac{1912}{25}\end{gathered}

<u>Alternate form:</u>

<u>u</u><u>=</u><u>76.48</u>

7 0
2 years ago
I am a 2 digit number the sum of my digits is 12. the ones digit is twice the tens digit? who am i?
Bas_tet [7]

Answer:

84

Step-by-step explanation:

let a be the 1's digit and b the 10's digit, then

a = 2b ← twice the 10's digit, thus

sum = 2b + b = 12, that is

3b = 12 ( divide both sides by 3 )

b = 4

and a = 2b = 2 × 4 = 8

The 2 digit number is 84

5 0
3 years ago
Consider the trinomial 6x2 + 13x + 6.
attashe74 [19]
In the given expression 6X² + 13X +6, we can easily identify the values of a, b and c. These values are a=6, b=13 and c=6
For the value of "ac", we have:
ac=6*6
ac=36
For a sum of b are 4, we have
ac+b=36+13=49
Therefore, the answer for the last question "The two numbers that have a product of ac and a sum of b are 4 and 9".
8 0
3 years ago
Read 2 more answers
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