Question

Which equation is y = –3x2 – 12x – 2 rewritten in vertex form? y = –3(x + 2)2 + 10 y = –3(x – 2)2 + 10 y = –3(x + 2)2 – 14 y = –3(x – 2)2 – 2

Answer 1

we have

$y =-3x^{2}-12x- 2$

Rewrite as perfect squares

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y+2 = -3x^{2} - 12x$

Factor the leading coefficient

$y+2 = -3(x^{2} +4x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y+2-12 = -3(x^{2} +4x+4)$

$y-10 = -3(x^{2} +4x+4)$

$y-10 = -3(x+2)^{2}$

$y=-3(x+2)^{2}+10$

therefore

the answer is the option

$y=-3(x+2)^{2}+10$

Answer 2

Y=-3(x+2)²+10 is the answer