2 years ago

Please help me with maths

Mathematics

1 answer:

liq [111]2 years ago

4 0

Answer:

Step-by-step explanation:

$a^{-m}=\frac{1}{a^{m}}\\\\4^{-8}=\frac{1}{4^{8}}$

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Solve the system of equations. If the system does not have one unique solution, determine the number of solutions to the system.

Licemer1 [7]

See photo. Hope it helps

3 0

2 years ago

Find the value of y. (6x - 13) (3y + 1) (8x - 61)

Korolek [52]

Answer:

y=1/3

Step-by-step explanation:

3y+1=0

3y=-1

3y/3=-1/3

y=-1/3

6 0

2 years ago

Find an equation of the tangent plane to the given surface at the specified point. z = ln(x − 8y), (9, 1, 0)

Archy [21]

Answer:

x - 8y - z = 1

Step-by-step explanation:

Data provided according to the question is as follows

f(x,y) = z = ln(x - 8y)

Now the equation for the tangent plane to the surface

For z = f (x,y) at the point P $(x_0,y_0,z_0)$ is

$z - z_0 = f_x(x_0,y_0)(x-x_0) + f_y(x_0,y_0)(y-y_0)\\$

Now the partial derivatives of f are

$f_x(x,y) = \frac{1}{x-8y} \\\\f_y(x,y) = \frac{8}{x-8y} \\\\P(x_0,y_0,z_0) = (9,1,0)\\\\f_z(9,1,0) = (\frac{1}{x-8y})_^{(9,1,0)}$

$\\\\=\frac{1}{9-8}$

= 1

Now

$f_y(9,1,0)=(\frac{8}{x-8y})_{(9,1,0)}\\\\ = -\frac{8}{9 - 8}$

= -8

So, the tangent equation is

$z - 0 = 1\times (x - 9) -8\times (y - 1)$

Now after solving this, the following equation arise

z = x - 9 - 8y + 8

z = x - 8y - 1

Therefore

x - 8y - z = 1

4 0

2 years ago

Solve for p, I don't know what else to add but yeah solve for p? Also explain

Charra [1.4K]

Answer:7

Step-by-step explanation:

6p-4+7p+3=90

13p-1=90

13p=91

p=7

4 0

2 years ago

Someone, please help my teacher doesn't want to help me and ugh I'm frustrated. Any help would be great!

maw [93]

Answer:

my brother said it is 5 and 10... but i do not know if it is

7 0

1 year ago

Please help me with maths​

Please help me with maths