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OverLord2011 [107]
4 years ago
12

(c) Is it possible for two recently made 50" TVs to have different screen lengths

Mathematics
1 answer:
grigory [225]4 years ago
6 0

Well, a 50" TV is measured from one corner of the screen to the other, so I believe that two TV's cannot have different lengths or widths.

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It always confuses me when they make me do the baby steps
VladimirAG [237]

Algebra always makes things sound harder than they actually are, and weird vocabulary can mix up the steps we knew so well.


Part 1: Multiply the first equation by a 2 so that you can cancel out the y variable.

6x - 2y = 0

5x + 2y = 22


Part 2: Actually cancel out the y variables, and combine like terms.

11x = 22


Part 3: Solve for "x" by dividing both sides by 11

x = 2


Part 4: Substitute the variable "x" with the value we just solved for in the original equation.

3(2) - y = 0

6 - y = 0

Then, solve for y by adding y to both sides

6=y


Solution Set = {2,6}

5 0
3 years ago
Identify two additional values for x and y in a direct variation relationship where y =11 when x=18
Ann [662]
In a direct variation relationship the values must satisfy that y = kx. This si y is always a constant value (k) times x.

So, you can find multiple values that meet this:

y = kx => k = y / x = 11 / 18

=> y = (11/18)x

Now you can give any value to x and fint the value of x that satisfy the relationship:

x           y = (11/18)x

1           11/18

2           11/18 * 2 = 11/9

18          11/18 * 18 = 11

36           11/18 * 36 = 22

So, there you have several additional values for x and y in the same relationship that y = 11 and x = 18, and you can find many more using the same rule: y = (11/18)*x
3 0
3 years ago
Beginning drivers soon learn that bringing an automobile to a stop requires greater distances for higher speeds. A formula that
BaLLatris [955]

The formula for the stopping distance in feet is

d=1.1v+0.055v^2

where v = Speed of the car in miles per hour.

The stopping distance for the car traveling at 15 mph is

d=1.1\times 15+0.055\times 15^2\\\Rightarrow d=28.875\approx 29\ \text{feet}

The stopping distance for the auto traveling at 15 mph is 29\ \text{feet}.

The stopping distance for the car traveling at 30 mph is

d=1.1\times 30+0.055\times 30^2\\\Rightarrow d=82.5\approx 83\ \text{feet}

The stopping distance for the auto traveling at 30 mph is 83\ \text{feet}.

Learn more:

brainly.com/question/19572178

brainly.com/question/24171613

4 0
3 years ago
Use a net to find the surface area of the cylinder. Use 3.14 for for pi.
AlladinOne [14]

Answer:

~150.79645 cm

Step-by-step explanation:

A=2πrh+2πr2=2·π·3·5+2·π·32≈150.79645

5 0
3 years ago
I need help on this ​
Anastaziya [24]

Answer:

(500÷1.8)÷60

By dividing 1.8 out of 500, u can know

5 0
3 years ago
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