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3 years ago

What is 3/8-1/6+5/12

Mathematics

1 answer:

Studentka2010 [4]3 years ago

4 0

<span>The answer to your question is 0.625</span>

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As accounts manager in your company, you classify 75% of your customers as "good credit" and the rest as "risky credit" dependin

Elena-2011 [213]

Answer:

The percentage of overdue accounts are held by customers in the "risky credit" category is 62.5%

Step-by-step explanation:

Customers in the "risky" category (25% of total accounts) allow their accounts to go overdue 50% of the time on average.

That means that on average, 12.5% of total accounts is overdue.

0.25*0.50 = 0.125

In the "good credit" category only 10% goes overdue. That means 7,5% of total accounts goes overdue in this category.

0.75*0.10=0.075

The total accounts that go overdue is 0.125+0.075 = 0.200.

The percentage of overdue accounts held by customers in the "risky credit" category is:

0.125/0.200 = 0.625 or 62.5%

4 0

3 years ago

Find the absolute value of 6/8

saul85 [17]

Answer:

0.75

Step-by-step explanation:

6 / 8 =

0.75

7 0

3 years ago

Listen

ozzi

Answer:

scale factor = $\frac{14}{5}$

Step-by-step explanation:

The scale factor is the ratio of corresponding sides, image to original.

scale factor = $\frac{7}{2.5}$ = $\frac{7(2)}{2.5(2)}$ = $\frac{14}{5}$

4 0

3 years ago

Without dividing or listing multiples, how can you tell if 61 is a multiple of 6?

Slav-nsk [51]

You check if it is even and that the sum of the digits is divisible by 3. That's the divisibility rule of 6.

6 0

3 years ago

Read 2 more answers

In the right triangle ?ABC, leg AC=6 cm and leg BC=8 cm. Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5. Find area of ?MN

Licemer1 [7]

Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.

To find : Area (ΔMNC)

Solution: In Δ ABC, right angled at C,

AC= 6 cm, BC= 8 cm

Using pythagoras theorem

AB² =AC²+ BC²

=6²+8²

= 36 + 64

→AB² =100

→AB² =10²

→AB =10

Also, AM:MN:NB=1:2.5:1.5

Then AM, MN, NB are k, 2.5 k, 1.5 k.

→2.5 k + k+1.5 k= 10

→ 5 k =10

Dividing both sides by 2, we get

→ k =2

MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm

As Δ ACB and ΔMNC are similar by SAS.

So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.

$\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}$

$\frac{Ar(ACB)}{Ar(MNC)}=4$

But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]

$\frac{24}{Ar(MNC)}=4$

→ Area(ΔMNC)=24÷4

→Area(ΔMNC)=6 cm²

4 0

3 years ago