Answer:
Step-by-step explanation:
The desired formula parameters for Newton's Law of Cooling can be found from the given data. Then the completed formula can be used to find the temperature at the specified time.
__
<h3>Given:</h3>

<h3>Find:</h3>
k
T(4)
<h3>Solution:</h3>
Filling in the given numbers, we have ...
185 = 68 +(208 -68)e^(-k·3)
117/140 = e^(-3k) . . . . . subtract 68, divide by 140
ln(117/140) = -3k . . . . . . take natural logarithms
k = ln(117/140)/-3 ≈ 0.060
__
The temperature after 4 minutes is about ...
T(4) = 68 +140e^(-0.060·4) ≈ 68 +140·0.787186
T(4) ≈ 178.205
After 4 minutes, the final temperature is about 178 °F.
Answer:
20
Explanation:
For the mean to be 21, the total of the 5 numbers must be 21*5= 105
To find what the final quiz score must be, we need to subtract the first 4 scores from 105. 105- 21- 24- 23- 17= 20
We can check this answer by finding the median of the 5 numbers now (17,20,21,24,23). The new median is 21 which means the final quiz score must be 20!
Hope this helped! :)
The inequality would be n/6 - 3 >/ 1. First, you would add 3 to both sides, leaving you with n/6 >/ 4. After that, you would just multiply 6 by 4 to get 24 as your answer.
Answer:
x/3 - 3
Step-by-step explanation:
⅓(x - 9)
⅓(x) - ⅓(9)
x/3 - 3
No like terms
One line passes through the points \blueD{(-3,-1)}(−3,−1)start color #11accd, (, minus, 3, comma, minus, 1, ), end color #11accd
mart [117]
Answer:
The lines are perpendicular
Step-by-step explanation:
we know that
If two lines are parallel, then their slopes are the same
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)
Remember that
The formula to calculate the slope between two points is equal to
<em>Find the slope of the first line</em>
we have the points
(-3,-1) and (1,-9)
substitute in the formula
<em>Find the slope of the second line</em>
we have the points
(1,4) and (5,6)
substitute in the formula
Simplify
<em>Compare the slopes</em>
Find out the product

therefore
The lines are perpendicular