Answer:
for (int h = k; h >= 0; h--)
Explanation:
From the list of given options, option C answers the question.
In the outer loop
Initially, k = 0
In the inner loop,
h = k = 0
The value of h will be printed once because h>=0 means 0>=0 and this implies once
To the outer loop
k = 1
The inner loop will always assume value of k;
So,
h = 1
This will be printed twice because of the condition h>=0 means 1>=0.
Since 1 and 0 are >=0; 1 will be printed twice
To the outer loop
k = 2
The inner loop
h = 2
This will be printed thrice because of the condition h>=0 means 2>=0.
Since 2, 1 and 0 are >=0; 2 will be printed thrice
To the outer loop
k = 3
The inner loop
h = 3
This will be printed four times because of the condition h>=0 means 3>=0.
Since 3, 2, 1 and 0 are >=0; 3 will be printed four times
<span>B. Efficiency
(</span><span>effective training </span><span>techniques)</span>
Answer:
a. new, running, waiting, ready, and terminated.
Explanation:
The process in a computer system can have different states and these are:
-New: When the process is created.
-Ready: When the process is waiting to be executed.
-Running: When the process is chosen to be executed.
-Waiting: When the process is expecting for something to happen.
-Terminated: When the process is not running anymore.
According to this, the answer is that the possible states of a process are: new, running, waiting, ready, and terminated.
Answer:
Person-to-Group
Explanation:
Person-to-Group communication involves one speaker and audience.
