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Alinara [238K]
3 years ago
6

Full form of http.wrong answer will be reported ​

Computers and Technology
2 answers:
vodomira [7]3 years ago
6 0

Answer:

So it is Hyper Text Transfer Protocol.

Hope it helps

nadezda [96]3 years ago
4 0

Answer:

The full form of HTTP is Hypertext Transfer Protocol.

Explanation:

  • It is an application protocol.
  • It is used for data communication.
  • It is used for transferring hypertext documents on the World Wide Web.
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Write an abstract data type for a queue in Java whose elements are generic elements of type T that have an associated integer pr
Nimfa-mama [501]

Answer:

See explaination

Explanation:

#include<iostream>

const int MAX=20;

class dque

{

private:

int arr[MAX];

int front,rear;

public:

dque();

void addqatbeg(char item);

void addqatend(char item);

int delqatbeg();

int delqatend();

void display();

int count();

};

dque::dque()

{

front=rear=-1;

for(int i=0;i<MAX;i++)

arr[i]=0;

}

void dque::addqatbeg(int item)

{

if(front==0&&rear==MAX-1){cout<<"\nDeque is full"<<endl;return;}

if(front==-1){front=rear=0;arr[front]=item;return;}

if(rear!=MAX-1)

{int c=count();int k=rear+1;

for(int i=1;i<=c;i++){arr[k]==arr[k-1];k--;}

arr[k]=item;front=k;rear++;

}

else{front--;arr[front]=item;}

}

void dque::addqatend(int item)

{

if(front==0&&rear==MAX-1){cout<<"\nDeque is full"<<endl;return;}

if(front==-1){front=rear=0;arr[rear]=item;return;}

if(rear==MAX-1){

int k=front-1;

for(int i=front-1;i<rear;i++){k=i;

if(k==MAX-1)arr[k]=0;

else arr[k]=arr[i+1];

}rear++;

arr[rear]=item;

}

int dque::delqatbeg()

{

if(front==-1){cout<<"\nDeque is empty"<<endl;return0;}

int item=arr[front];

arr[front]=0;

if(front==rear)front=rear=-1;

else

front++;

return item;

}

int dque::delqatend()

{

if(front==-1){cout<<"\nDeque is empty"<<endl;return 0;}

int item=arr[rear];

arr[rear]=0;

rear--;

if(rear==-1)front=-1;return item;

}

void dque::display()

{

cout<<endl<<"front->";

for(int i=0;i<MAX;i++)cout<<""<<arr[i];cout<<"<-rear";

}

int dque::count()

{

int c=0;

for (int i=0;i<MAX;i++){if(arr[i]!=0)c++;}

return c;}

}

7 0
3 years ago
Read 2 more answers
HTML code to display square bullets in an unordered list​
Solnce55 [7]

Answer:

<!DOCTYPE html>

<html>

<body>

<h2>Unordered List with Square Bullets</h2>

<ul style="list-style-type:square;">

 <li>Coffee</li>

 <li>Tea</li>

 <li>Milk</li>

</ul>

</body>

</html>

5 0
3 years ago
Does anyone know the answer to 2 and 3
docker41 [41]
No because u ain’t put the question up here for someone to answer
6 0
3 years ago
5) Match the following.
statuscvo [17]
1 .hub
2.server
3.Network Interface
4.Workstation


I’m sorry if I’m wrong :(

I hope it helps
8 0
3 years ago
#Write a function called 'string_type' which accepts one #string argument and determines what type of string it is. # # - If the
deff fn [24]

Answer:

I am writing a Python program:

def string_type(string):

   if string=="":  //if the string is empty

       return "empty"

   elif string.count(".")>1:  #if the period sign occurs more than once in string

       if string.count("\n"):  #checks if the new line occurs in the string

           return "page"  #if both the above cases are true then its a page

       return "paragraph"  # if the period sign condition is true then its a para

   elif string.count(" ")>=1:  #if no of spaces in string occur more than once

       return "sentence"  #returns sentence

   elif len(string)==1:  # if length of the string is 1 this

       return "character"  #returns character

   else:  #if none of the above conditions is true then its a word

       return "word" #returns word

Explanation:

def string_type(string):  this is the definition of method string_type which takes a string as argument and determines whether the type of string is a word, paragraph, page, sentence or empty.

if string=="" this if condition checks if the string is empty. If this condition is true then the method returns "empty"

elif string.count(".")>1  This condition checks if the string type is a paragragh

string.count(".")>1   and if string.count("\n") both statements check if the string type is a page.

Here the count() method is used which is used to return the number of times a specified string or character appears in the given string.

Suppose the string is "Paragraphs need to have multiple sentences. It's true.\n However, two is enough. Yes, two sentences can make a paragraph."

The if condition first checks if count(".")>1 which means it counts the occurrence of period i.e. "." in the string. If the period occurs more than once this means it could be a page. But it could also be a paragraph so in order to determine the correct string type another if statement if string.count("\n") inside elif statement determines if the string is a page or not. This statement checks the number of times a new line appears in the string. So this distinguishes the string type paragraph from string type page.

elif string.count(" ")>=1: statement determines if the string is a sentence. For example if the string is "i love to eat apples." count() method counts the number of times " " space appears in the string. If the space appears more than once this means this cannot be a single word or a character and it has more than one words. So this means its a sentence.

  elif len(string)==1:  this else if condition checks the length of the string. If the length of the string is 1 this means the string only has a single character. Suppose string is "!" Then the len (string) = 1 as it only contains exclamation mark character. So the method returns "character" . If none of the above if and elif conditions evaluates to true then this means the string type is a word.

8 0
3 years ago
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