Answer:
A. a collection of organized data.
Explanation:
It can be a data source, or a database, an excel sheet. or access database. However, it must be well-formatted and hence organized. filtering of data is not necessary, as well as it is not any barrier to the number of the set of data, or the data being sorted. Unsorted data is also fine, and multiple set of data is also fine. It must be known that a data source can be formed from multiple sets of data through the query. And the resultant data source can be used by the mail merge. However, the data source must be a collection of organized data. Hence, A is the correct answer.
Answer: A. Multicast
Explanation:
Here we are given a situation where it is necessary for the device to stream media to all the PCs connected across the LAN. But as the they are unable to stream the media then it is a problem in the multicast TCP/Ip technology.
Multicasting enables to transfer information or messages from one to many or many to many. Here as a single device is responsible for streaming the content to other PCs across the LAN, therefore it is necessary that multicast has been properly implemented.
Option B is incorrect as it is not a scenario of broadcast as in broadcasting all the receivers must get the streaming however here if a PC does not want to receive the media stream it cannot receive for which multicasting is required.
Option C is incorrect as here we are not talking of one to one communication.
Option D is incorrect as here we cannot have more than one route to send the media content except the LAN.
Answer:
Check the explanation
Explanation:
#include <iostream>
#include <iomanip>
using namespace std;
int getIQ(); // return the score
void printEvaluation(int);
int main()
{
int IQ = 0;
IQ = getIQ();
printEvaluation(IQ);
return 0;
}
int getIQ()
{
int score = 0;
cout << "Please enter your IQ Score to receive your IQ Rating:\n";
cin >> score;
return score;
}
void printEvaluation(int aScore)
{
cout << "IQ Score: " << aScore << " IQ Rating: ";
if (aScore <= 100)
{
cout << "Below Average\n";
}
else if (aScore <= 119)
{
cout <<"Average\n";
}
else if (aScore <= 160)
{
cout << "Superior\n";
}
else if (aScore >= 160 )
{
cout << "Genius\n";
}
}
Answer:-
(10111.001)₂
Explanation:
To convert a decimal number to a binary number we have to constantly divide the decimal number by 2 till the decimal number becomes zero and the binary number is writing the remainders in reverse order of obtaining them on each division.
Hence the binary number is 10111.001
To convert binary to hexa decimal we to make a group 4 binary bits starting from the decimal and moving outwards if the last group is not of 4 then add respective 0's and write the corresponding hexa decimal number.
<u>0001</u> <u>0111</u> . <u>0010</u>
1 7 2
Hence the hexadecimal number is 17.2
Answer:
you will know if your audience is engaged.
Explanation:
