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babymother [125]
3 years ago
8

What is the sum of the geometric sequence 3, 15, 75, … if there are 8 terms?

Mathematics
2 answers:
lidiya [134]3 years ago
6 0

Answer:

292,968

Step-by-step explanation:

Step 1: Use geometric sequence formula s_n=\frac{a1r^n}{1-r}

S_n & n= the sum of geometric sequence & terms in total (8)

r= common ratio (5)

a_1= first term in sequence (3)

<h2>s_8=\frac{3(5)^(^8^)}{ 1-5 }\\s_8=\frac{(3)390625}{-4}\\s_8= \frac{1171875}{ -4 }\\s_8=292968</h2><h2 />

Firlakuza [10]3 years ago
4 0
If you would like to know the sum of the geometric sequence, you can calculate this using the following steps:

3, 15, 75, 75 * 5 = 375, 375 * 5 = 1875, 1875 * 5 = 9375, 9375 * 5 = 46875, 46875 * 5 = 234375

<span>3 + 15 + 75 + 375 + 1875 + 9375 + 46875 + 234375 = </span>292,968

The correct result would be 292,968.
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Answer:

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Step-by-step explanation:

Let's solve your equation step-by-step.

3(6d−24)=6(12+3d)

Step 1: Simplify both sides of the equation.

3(6d−24)=6(12+3d)

(3)(6d)+(3)(−24)=(6)(12)+(6)(3d)(Distribute)

18d+−72=72+18d

18d−72=18d+72

Step 2: Subtract 18d from both sides.

18d−72−18d=18d+72−18d

−72=72

Step 3: Add 72 to both sides.

−72+72=72+72

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Answer:

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Step-by-step explanation:

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