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iVinArrow [24]
3 years ago
5

Como simplifica o seguinte produto notável: (x+2)²​

Mathematics
1 answer:
gogolik [260]3 years ago
7 0
(x+2)^2

x^2+2x · 2+2^2

x^2+4x+4
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55/(4+1)+3-three cubed​
Charra [1.4K]

Answer:38

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The area of a rectangle is 30+12x what are 3 possibilities for the length and width of the rectangle
Stolb23 [73]

In order to find the three possibilities, you must first think of common factors between 30 and 12:

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

Factors of 12: 1, 2, 3, 4, 6, 12

We can find three common factors between the two numbers: 2, 3, and 6. So these are three widths that we can use. The length can be found by factoring out the numbers from 30+12x (we can't factor out x):

30+12x=2(15+6x)      Width: 2      Length: 15+6x

20+12x=3(10+4x)      Width: 3      Length: 10+4x

20+12x=6(5+2x)       Width: 6      Length: 5+2x

4 0
3 years ago
Help plz ?????????????
Lyrx [107]

Answer:

3443            

 ———— =<u><em> C. 202</em></u>

  17      

Step-by-step explanation:

Step  1  :

                  3443

Simplify   ————

                      17

Final result :

 3443            

 ———— = 202.52941

  17              

Processing ends successfully

plz mark em as brainliest :)

8 0
3 years ago
How to find the formula for the sum of series that is not arithmetic nor geometric?please give examples
Roman55 [17]
Im not sure tho sorry for your inconvenience
8 0
3 years ago
The proof that AMNS AQNS is shown.
FrozenT [24]

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e   MS=SQ

In ΔMNS and ΔQNS

MN=QN       (∵ MNQ is isosceles triangle)

∠NMS=∠NQS     (∵ MNQ is isosceles triangle)

MS=SQ         (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

3 0
3 years ago
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