Question

Factor completely 18x2 − 21x −15.

Answer 1

Answer:

The factors of equation $18x^2-21x-15$ is $=3((3x-5)(2x+1))$

Step-by-step explanation:

Given : Equation $18x^2-21x-15$

We have to factorize the given equation $18x^2-21x-15$

Consider the given equation$18x^2-21x-15$

Taking 3 common from each term, we have,

$=3\left(6x^2-7x-5\right)$

We will solve the given equation using middle term split method,

-7x can be written as 3x -10x

Equation becomes,

$=3(6x^2+3x-10x-5)$

Taking 3x common from first two term and -5 common from last two terms, we have,

$=3(3x(2x+1)-5(2x+1))$

Taking (2x+1) common, we have,

$=3((3x-5)(2x+1))$

Thus, The factors of equation $18x^2-21x-15$ is $=3((3x-5)(2x+1))$

Answer 2

3(6x² + 3x - 10x - 5)
= 3(3x(2x + 1) - 5(2x + 1))
= 3(2x + 1)(3x - 5)