Answer: It is 4
Step-by-step explanation:
Becasue
1/2=2/x
x=2*2
x=4
Answer:
She can chose 2 books from 8 books in 28 different way.
Step-by-step explanation:
In the given scenario the member has to chose 2 books from a group of 8 books. The order of choosing books does not matter. For example if the books are A,B,C,D,E,F,G and H, and the member picks books A and B or books B and A, she is picking up the same books. This means order of selection does not matter here, so this is a problem of combinations.
We have to form combination of 8 books taken 2 at a time i.e. 8C2
The general formula of combination is:
![nCr=\frac{n!}{r!(n-r)!}](https://tex.z-dn.net/?f=nCr%3D%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D)
Using the values of n=8 and r=2, we get:
![8C2=\frac{8!}{2!(8-2)!}=28](https://tex.z-dn.net/?f=8C2%3D%5Cfrac%7B8%21%7D%7B2%21%288-2%29%21%7D%3D28)
This means, she can chose 2 books from 8 books in 28 different ways.
Answer:
12.87
Step-by-step explanation:
13.37 x3 = 40.11
13.51x2= 27.02
40.11+ 27.02= 67.13
80.00-67.13= 12.87
Answer:
we can not reject any value
Step-by-step explanation: From data we can test the highest and the lowest value to evaluate if one of these values are out of certain confidence Interval
If we established CI = 95 % then α = 5 % and α/2 = 0,025
From data we find the mean of the values
μ₀ = 12,03 and σ = 0,07
From z table we find z score for 0,025 is z(c) = ± 1,96
So limits of our CI are:
12,03 + 1,96 = 13,99
12,03 - 1,96 = 10,07
And all our values are within ( 10,07 , 13,99)
So we can not reject any value
Answer:
there aren't any options. but quadrant four would have a (x,-y) set up. positive x-values, but negative y-values.