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Sonja [21]
3 years ago
5

John swam 40 minutes what fraction of one hour is this

Mathematics
1 answer:
Volgvan3 years ago
6 0
2/3 because 60 is in a hour and if you take away the zeros in 60 and 40 you get 4/6 and then you can simplify to 2/3
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+22 + +14 + -10 + +10 + -22 + +14 = n
professor190 [17]

Answer:

Solve for n:

28 = n

Hint: | Reverse the equality in 28 = n in order to isolate n to the left hand side.

28 = n is equivalent to n = 28:

Answer: n = 28

Step-by-step explanation:

6 0
3 years ago
What is the volume of this rectangular prism?
kolezko [41]

Answer:

  • 105 in³.

Step-by-step explanation:

<u>Given numbers:</u>

  • 7, 3, and 5.

<u>Given equation:</u>

  • 7 * 3 * 5.

<u>Solve:</u>

  • 7 * 3
  • = 21 * 5
  • = 105.

Volume is 105 in³.

4 0
2 years ago
Read 2 more answers
If the graph of f(x) = |x| is shifted up 7 units, which equation represents the new graph?
Pie
F(x)=|x|+7 is the equation
7 0
3 years ago
The width of a rectangle is 8 inches less than the length. The perimeter is 76 inches. Find the length and the width.
REY [17]
L=30in
w Width

in
P Perimeter

in
Width is 8 and perimeter is 76
3 0
4 years ago
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
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