n + d = 63
5N + 10d = 525
5n(63-d) + 10d = 525
315-5d+10d=525
5d=210
d=42
n = 63-42 = 21
Check 42 x .10 = 4.20, 21 x .05 = 1.05. 4.20 + 1.05 = 5.25
Answer: y = (-1/2)x + 2
Step-by-step explanation:
Answer:
34% of lightbulb replacement requests numbering between 47 and 52
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 52
Standard deviation = 5
Between 47 and 52:
52 is the mean and 47 is one standard deviation below the mean.
By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean.
Since the normal distribution is symmetric, of those, 34% are within 1 standard deviation below the mean and the mean(47 and 52) and 34% are within the mean and one standard deviation above the mean(52 and 57).
So
34% of lightbulb replacement requests numbering between 47 and 52
Answer:
1.75
Step-by-step explanation:
Let the number to be increased be x
If x is to be increased by 75% then the result after the increase T may be expressed as
T = x + 75% * x
T = x + 0.75x
T = 1.75x
As such when x is increased by 75%, the result is the product of x and 1.75 (the multiplier).