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2 years ago

7

Answers for both boxes please

1 answer:

Dafna11 [192]2 years ago

7 0

Answer y=25/3 or 8.33333 and x=0.4444443

Step-by-step explanation:

y=4(y-7/3)+3 y=4y-28+3 y=4y-25

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A climber who is 6 feet tall, casts a shadow that is 20 feet tall, at the same time that a tree casts a shadow which is 90 feet

Sergio039 [100]

The tree is 76ft. long

3 0

2 years ago

How many solutions does the system have? \begin{cases} 5y =15x-40 \\\\ y = 3x-8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ 5y=15x−40 y=3x−8 C

Ksenya-84 [330]

Answer:

(C) Infinitely many solutions

Step-by-step explanation:

Converting the lines into the from $ax+by+c=0$

$5y=15x-40\\\Rightarrow 15x-5y-40=0$

$y=3x-8\\\Rightarrow 3x-y-8=0$

$\dfrac{a_1}{a_2}=\dfrac{15}{3}=5$

$\dfrac{b_1}{b_2}=\dfrac{-5}{-1}=5$

$\dfrac{c_1}{c_2}=\dfrac{-40}{-8}=5$

So, $\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}$ .

Hence, these lines have infinitely many solutions.

3 0

2 years ago

8. The angle measures of a triangle are shown in the diagram. What is the value of x? A. 20 B. 15. C. 32 D. 40 I WILL GIVE BRAIN

AfilCa [17]

Answer:

D) 40

Step-by-step explanation:

triangles equal to 180 degrees

2x+10+x+50=180

3x+60=180

3x=120

x=40

7 0

5 months ago

One of the roots of the equation x²-5x +q=0 is 2. Find the other root and the value of the coefficient q.

yuradex [85]

Answer:

Other root: $x=3$

$q=6$

Step-by-step explanation:

If $x=2$ , then $x-2=0$ .

Therefore:

$x^2-5x+q=0$

$2^2-5(2)+q=0$

$4-10+q=0$

$-6+q=0$

$q=6$

This means that the other root is $x=3$ since $(x-2)(x-3)=x^2-5x+6$

5 0

1 year ago

SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP

nata0808 [166]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

Step-by-step explanation:

Given the system of the equations

$x+3y=5;\:x=-6y+14$

solving by elimination method

$\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}$

$\mathrm{Arrange\:equation\:variables\:for\:elimination}$

$\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}$

$x+6y=14$

$-$

$\underline{x+3y=5}$

$3y=9$

$\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}$

solve $3y=9$ for $y$ :

$3y=9$

$\frac{3y}{3}=\frac{9}{3}$

$y=3$

$\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3$

Solve $x+3\cdot \:3=5$ for x:

$x+3\cdot \:3=5$

$x+9=5$

$x=-4$

Therefore,

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

6 0

2 years ago