Is this problem right?
1 answer:
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Answer:
See the proof below.
Step-by-step explanation:
For this case we need to proof that: Let be independent random variables with a common CDF
. Let
be their ECDF and let F any CDF. If
then
Proof
Let different values in the set {
} and we can assume that
represent the number of
that are equal to
.
We can define and assuming the probability
.
For the case when for any
then we have that the
And for the case when all and for at least one
we know that
for all the possible values
. So then we can define the following ratio like this:
So then we have that:
And the log for a number is 0 or negative when the number is between 0 and 1, so then on this case we can ensure that
And with that we complete the proof.
Figure is missing, so i have attached it.
Answer:
it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft
Step-by-step explanation:
The standard form of equation of an ellipse is;
x²/a² + y²/b² = 1
From the figure in the image attached, we can see that the radius is; a = 52/2 = 26 ft
While the value of b = 13 ft
Thus;
x²/26² + y²/13² = 1
x²/676 + y²/169 = 1
We want to find the height of the archway of the bridge 5 feet from the center.
Thus, we will plug in 5 for x to get;
5²/676 + y²/169 = 1
(25/676) + (y²/169) = 1
Multiply through by 676 to get;
25 + 4y² = 676
4y² = 676 - 25
y² = 651/4
y² = 162.75
y = 12.76 ft
Thus height of the truck is 12 ft and so it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft
