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vodka [1.7K]
3 years ago
5

Is this problem right?

Mathematics
1 answer:
Andrews [41]3 years ago
6 0
Yes those are right. all the steps and answers are correct.
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!!!KHAN ACADEMY!!! help please
barxatty [35]
Use photomath lollllll
3 0
2 years ago
What is the gradient of the graph shown ? Give your answer in its simplest form
Sedbober [7]

Answer:

-2

Step-by-step explanation:

choose any point on the graph

3 0
2 years ago
Two jets leave an airport at the same time, flying in opposite directions. The first jet is traveling at three hundred seventy-s
gladu [14]
Here is the set using D = rt.


Jet 1:

rate = 377 mph

time = x

Distance = 9128 miles

Jet 2:

rate = 275 mph

time = x

Distance = 9128 miles

Equation:

377x + 275x = 9128

You finish.
8 0
3 years ago
Write an equation for the statement: A kilogram is equal to approximately 2.2 pounds. A cinder block weighs x pounds. A brick ha
navik [9.2K]

the total mass in kilograms y of the cinder block and brick is  y=0.45x + 0.6 .

<u>Step-by-step explanation:</u>

Here we have , A kilogram is equal to approximately 2.2 pounds. A cinder block weighs x pounds. A brick has a mass of 0.6 kilogram. We need to find What is the total mass in kilograms y of the cinder block and brick . Let's find out :

According to given data in question ,

⇒ 1kg = 2.2pounds

⇒ 1(pounds) = \frac{1}{2.2}kg

A cinder block weighs x pounds and a brick has a mass of 0.6 kilogram . Let total mass in kg of the cinder block and brick is y , i.e.

⇒ y (kg)= x (pounds) + 0.6 kg

⇒ y (kg)= x (\frac{1}{2.2}kg) + 0.6 kg

⇒ y=0.45x + 0.6

Therefore , the total mass in kilograms y of the cinder block and brick is  y=0.45x + 0.6 .

7 0
3 years ago
Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb
Umnica [9.8K]

Answer:

It would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.  

Since  

z =  ax^2  + by^2

For this case, the gradient of your function would be

\nabla z  = (2ax , 2by)

And  -1  times the gradient of your function would be

-\nabla z  = (-2ax , -2by)\\

Then, at

 (1,1,a+b),\\x = 1 \\y = 1

So it would go towards

v = (-2a,-2b)

The magnitud of that vector is

|v| =  2\sqrt{a^2+b^2}

and to conclude it would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

6 0
3 years ago
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