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2 years ago

Expanded form of 3(4x+5y)

Mathematics

1 answer:

PIT_PIT [208]2 years ago

3 0

= 12x + 15y because 3 x 4x = 12x and 3 x 5y = 15y

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So, I have a question if anyone can answer soon.

Sonja [21]

Answer:

You're right must be a different problem

Step-by-step explanation:

You know this, but just to verify:

1. Find Common Denominator:

6 15/21 - 6 7/21

2. Subtract

6 15/21 - 6 7/21 = 8/21 feet

7 0

3 years ago

List least to greatest <br> -3/8, 5/16, -0.65, 2/4

amid [387]

-0.65
-3/8
2/4
5/16
I hope this is right, the negatives should go first because you are taking away, then positives

8 0

3 years ago

Shaneeka is saving $5.75 of her allowance each week to buy a new camera that costs $51.75. How many weeks will she have to save

nika2105 [10]

Answer:

a. 9 weeks

Step-by-step explanation:

$51.75÷$5.75= 9 weeks

She will have to save 9 weeks to be able to afford the camera.

6 0

3 years ago

22<br> 1 point<br> If f (x) = 7– 41, what is f (-10)?

Anettt [7]

Answer:

f(x)+41 f(-10)=7

Step-by-step explanation:

5 0

3 years ago

Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr

Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, $A(10) = 0.7278A(0)$ . We use this to find k.

$A(t) = A(0)e^{-kt}$

$0.7278A(0) = A(0)e^{-10k}$

$e^{-10k} = 0.7278$

$\ln{e^{-10k}} = \ln{0.7278}$

$-10k = \ln{0.7278}$

$k = -\frac{\ln{0.7278}}{10}$

$k = 0.03177289938
$

Then

$A(t) = A(0)e^{-0.03177289938t}$

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

$A(5) = A(0)e^{-0.03177289938*5}$

$A(5) = 0.8531$

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0

3 years ago