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Dovator [93]
3 years ago
15

30 points! Find the four arithmetic means between -17 and 32.

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0

Answer: - 7.2 , 2.6 , 12.4 and 22.2

Step-by-step explanation:

Let the arithmetic means be p , q , r ,s , therefore , the sequence becomes:

-17 , p , q , r , s , 32

The first term (a ) = -17

Last term (L) = 32

common difference (d) = ?

number of terms (n ) = 6

We will use the formula for calculating the last term to find the common difference. That  is

L = a + (n - 1 ) d

Substituting the values , we have

32 = -17 + (6-1) d

32 = -17 + 5d

32 + 17 = 5d

49 = 5d

Therefore: d = 9.8

We can therefore find the values of p , q , r , and s

p is the second term , that is

p = a + d

p = -17 + 9.8

p = -7.2

q = a + 2d

q = - 17 + 19.6

q = 2.6

r = a + 3d

r = - 17 + 29.4

r = 12.4

s = a + 4d

s = - 17 + 39.2

s = 22.2

Therefore : the arithmetic means are : - 7.2 , 2.6 , 12.4 and 22.2

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Asked on December 20, 2019 by

Ziya Vïvəķ

A cylindrical container with diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32×22cm×14cm). Find the rise in the level of water when the solid is completely submerged.

MEDIUM

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ANSWER

Given,

Diameter of the base of the cylindrical container d=56 cm

Hence, radius of the base of the cylindrical container r=

2

56

=28 cm

Dimensions of rectangular solid is (32 cm×22 cm×14 cm)

We know that when a body is completely submerged in a container containing water,

the rise in the volume of water in the container is equal to the volume of the body.

Let, the water rises to a height h.

Hence,

Volume of water rises in cylindrical container =Volume of the rectangular solid

πr

2

h=32×22×14 cm

3

7

22

×(28)

2

×h=9856 cm

h=

22×784

9856×7

cm

h=4 cm

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Javier is purchasing a bouquet of roses from a floral shop. He wants the bouquet to have at least 12 roses but wants to spend le
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Also, Red roses cost $2.75 each and white roses cost $3.50 each and he wants to spend less than $35.

i.e. $2.75(No. of red roses)+$3.50(No. of white roses)≤ $35

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