1/5x-2/3x15 =30
0.2x-30/3=30
0,2x-10=30
0,2x-10+10=30+10
0,2x=40
0.2x x5=40x5
x=200
We know that C is dependent on how many hours of service was done. We also know that C is linearly dependent on how many hours of service was done because it's a constant $50 per hour.
So, the equation would be a linear equation in the form C = 50h + L where h is the number of hours and L is the y-intercept.
Since there is an initial charge of $25, when h = 0, C = $25 -> L = $25.
So, the equation is C = 50h + 25.
Answer:
![\sf \dfrac{2}{3} = \dfrac{32}{48} = \dfrac{30}{45}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B2%7D%7B3%7D%20%20%3D%20%5Cdfrac%7B32%7D%7B48%7D%20%20%3D%20%5Cdfrac%7B30%7D%7B45%7D)
<h3><u>For the 1st part</u></h3>
![\sf \rightarrow \dfrac{2}{x} = \dfrac{32}{48}](https://tex.z-dn.net/?f=%5Csf%20%5Crightarrow%20%5Cdfrac%7B2%7D%7Bx%7D%20%3D%20%5Cdfrac%7B32%7D%7B48%7D)
![\sf \rightarrow 2(48)= {32x}](https://tex.z-dn.net/?f=%5Csf%20%5Crightarrow%202%2848%29%3D%20%7B32x%7D)
![\sf \rightarrow 32x= 96](https://tex.z-dn.net/?f=%5Csf%20%5Crightarrow%2032x%3D%2096)
![\sf \rightarrow x = 3](https://tex.z-dn.net/?f=%5Csf%20%5Crightarrow%20x%20%3D%203)
<h3><u>For the 2nd part</u></h3>
<u />![\rightarrow \sf \dfrac{32}{48} = \dfrac{30}{y}](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20%5Cdfrac%7B32%7D%7B48%7D%20%3D%20%5Cdfrac%7B30%7D%7By%7D)
![\rightarrow \sf {32y} = 30(48)](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20%7B32y%7D%20%3D%2030%2848%29)
![\rightarrow \sf {32y} = 1440](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20%7B32y%7D%20%3D%201440)
![\rightarrow \sf y = 45](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20y%20%3D%2045)
The factors are x=6 and x=-1