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romanna [79]
4 years ago
12

If y is directly proportional to x square and y equal 1/8 when x = 1/2 what is the positive value of x when y it was 9/2?

Mathematics
1 answer:
mojhsa [17]4 years ago
8 0

Answer:

d

Step-by-step explanation:

Given y is directly proportional to x² then the equation relating them is

y = kx² ← k is the constant of proportion

To find k use the condition y = \frac{1}{8} when x = \frac{1}{2}, then

\frac{1}{8} = k(\frac{1}{2} )² = \frac{1}{4} k ( multiply both sides by 8 )

1 = 2k ( divide both sides by 2 )

k = \frac{1}{2}

y = \frac{1}{2} x² ← equation of proportion

When y = \frac{9}{2} , then

\frac{9}{2} = \frac{1}{2} x² ( multiply both sides by 2 )

9 = x² ( take the square root of both sides )

x = ± \sqrt{9} = ± 3

with positive value x = 3 → d

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