3 years ago

I am not quite sure how to do these.

1 answer:

6 0

Sin (Π/2 - theta) = sin(Π/2) * cos(theta) - cos(Π/2) * sin (theta)
and as we know sin(Π/2) =1 , cos(Π/2)=0
so sin(Π/2 - theta) = 1* cos(theta) - 0* sin(theta)= cos(theta)
2nd cos(180+ theta) = cos(180)*cos(theta) - sin(180)* sin(theta)
,,, so , cos(180+theta) = -cos(theta)

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