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lora16 [44]
3 years ago
5

I am not quite sure how to do these.

Mathematics
1 answer:
EleoNora [17]3 years ago
6 0
Sin (Π/2 - theta) = sin(Π/2) * cos(theta) - cos(Π/2) * sin (theta)
and as we know sin(Π/2) =1 , cos(Π/2)=0
so sin(Π/2 - theta) = 1* cos(theta) - 0* sin(theta)= cos(theta)
2nd cos(180+ theta) = cos(180)*cos(theta) - sin(180)* sin(theta)
,,, so , cos(180+theta) = -cos(theta)
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Step-by-step explanation:


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There is 1500 ft of fencing available to make 6 identical pens. Find the maximum area for EACH pen (meaning maximum of one pen).
hjlf

Answer:

The maximum area is therefore is 93750 ft²

Step-by-step explanation:

The given parameter are;

The a]length of fencing available = 1500 ft.

The perimeter of the figure = 9·x + 4·y

Therefore, 9·x + 4·y = 1500 ft.

The area of the figure = 6 × (x × y) = 3·x × 2·y

From the equation for the perimeter, we have;

9·x + 4·y = 1500

y = 1500/4 - 9/4·x = 375 - 9/4·x

y = 375 - 9/4·x

Substituting the value of y in the equation for the area gives;

Area = 3·x × 2·y = 3·x × 2·(375 - 9/4·x) = 2250·x - 27/2·x²

Area = 2250·x - 27/2·x²

The maximum area is found by taking the derivative and equating to zero as follows;

d(2250·x - 27/2·x²)/dx = 0

2250 - 27·x = 0

x = 2250/27 = 250/3

x = 250/3

y = 375 - 9/4·x = 375 - 9/4×250/3 = 187.5

The maximum area is therefore, 3·x × 2·y = 3 × 250/3 × 2 × 187.5 = 93750 ft²

The maximum area is therefore = 93750 ft.²

4 0
3 years ago
The equation of the line EF is y=2x+1. Write an equation of a line parallel to line EF in slope intercept form that contains poi
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Y = 2x + 2

The slope must stay the same since they are parallel and the new point would be the y intercept. 
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3 years ago
Read 2 more answers
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