We need to compute the diagonal of yhe square.
d²=7²+7²=49×2cm²
d=7×sqrt(2)=7×1.41=9.87cm.
The diagonal we just computed is the diameter of the circle that contains the square.
Since d=9.87 < 11, then indeed, the square fits inside the circle, without touching it.
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Answer:
C. x^2 + 3
Step-by-step explanation:
Substitute for f(x) and g(x) and simplify.
(f -g)(x) = f(x) -g(x)
(f -g)(x) = (2x^2 +2) -(x^2 -1) = 2x^2 +2 -x^2 +1
(f -g)(x) = x^2 +3
The radius is half the diameter, so the formula would be r=d divided by 2
−
9
Explanation:
(
3
i
)
2
=
9
i
2
i
2
=
−
1
,
therefore,
9
i
2
=
9
⋅
(
−
1
)
=
−
9
The triangle shown is a Pythagorean triple with lengths of 3-4-5.
AC = 3
AB = 4
BC = 5