This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get
i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:
where is a compact way to indicate both solutions
and
, while
are the coefficients of the quadratic equation, i.e. we consider the polynomial
.
So, in your case, we have
Plug those values into the formula to get
So, the two solutions are
You are constructing a tangent line from a point outside a given circle to the circle is to draw a circle and a point outside th
e circle. You have drawn the circle, a point outside the circle and connected the center of the circle to the point outside the circle. You found the midpoint of the segment. Next you must use your compass. After you set it, where should you put the point?
A.) the center of the circle
B.) the point outside the circle
C.) the midpoint of the segment
D.) the intersection of the segment and the circle
A.) the center of the circle
B.) the point outside the circle
C.) the midpoint of the segment
D.) the intersection of the segment and the circle
2 answers:
Answer with explanation:
1.Draw a Circle of any radius.
2.Take a point outside on the circle.
3.Draw a line segment Joining center to the point lying outside.
4.Draw the perpendicular bisector of that line segment.
5.Keep one end of the compass on the midpoint of the line segment, and other end of the compass on the center or other end of line segment,and draw a circle.
6.The points where this circle,cuts the circle drawn in the beginning,are the points,from where you can draw tangents which will intersect at the point which lies outside that we have taken in the beginning.
Option C : the midpoint of the segment
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