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ra1l [238]
2 years ago
5

You are constructing a tangent line from a point outside a given circle to the circle is to draw a circle and a point outside th

e circle. You have drawn the circle, a point outside the circle and connected the center of the circle to the point outside the circle. You found the midpoint of the segment. Next you must use your compass. After you set it, where should you put the point?
A.) the center of the circle
B.) the point outside the circle
C.) the midpoint of the segment
D.) the intersection of the segment and the circle

Mathematics
2 answers:
Alja [10]2 years ago
6 0
I think its C I am not sure hope it helps 

d1i1m1o1n [39]2 years ago
3 0

Answer with explanation:

1.Draw a Circle of any radius.

2.Take a point outside on the circle.

3.Draw a line segment Joining center to the point lying outside.

4.Draw the perpendicular bisector of that line segment.

5.Keep one end of the compass on the midpoint of the line segment, and other end of the compass on the center or other end of line segment,and draw a circle.

6.The points where this circle,cuts the circle drawn in the beginning,are the points,from where you can draw tangents which will intersect at the point which lies outside that we have taken in the beginning.

Option C : the midpoint of the segment

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Select whether the equation has a solution or not.<br> √x = 7
Ierofanga [76]

Answer:

x = 49

The equation does have a solution

Step-by-step explanation:

The sqrt of x = 7, does have a solution. Simply remove the radical, and raise each side by the index of the radical.

In more basic terms, what number has the sqrt of 7? 7^2 is equal to 49!

6 0
3 years ago
The distribution of scores on a recent test closely followed a Normal Distribution with a mean of 22 points and a standard devia
maksim [4K]

6.68% of the students scored at least 19 points on this test while the 85 percentile has a test score of 24.08 points

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ \mu=mean.\sigma=standard\ deviation, x=raw\ score\\\\Given\ that\ mean(\mu)=22,standard \ deviation (\sigma)=2\\\\For\ x>19:\\\\z=\frac{22-19}{2}=1.5

P(x > 19) = P(z > 1.5) = 1 - P(z < 1.5) = 1 - 0.9332 = 0.0668

6.68% of the students scored at least 19 points on this test

b) 85 percentile corresponds to a z score of 1.04

z=\frac{x-\mu}{\sigma}\\\\1.04 =\frac{x-22}{2} \\\\2.08=x-22\\\\x=24.08

The 85 percentile has a test score of 24.08

Find out more at: brainly.com/question/25012216

7 0
3 years ago
What is the answer for 4x+y=0
leva [86]
Y=-4x because all you have to do is move the variable to the right by adding its opposite to both sides. So 4x+y-4x=0-4x. Then eliminate the opposites y=0-4x

Your welcome
7 0
3 years ago
A log is floating on swiftly moving water. A stone is dropped from rest from a 50.8-m-high bridge and lands on the log as it pas
TiliK225 [7]

Answer:

Horizontal distance between the log and the bridge when the stone is released = 17.24 m

Step-by-step explanation:

Height of bridge, h = 50.8 m

Speed of log = 5.36 m/s

We need to find the horizontal distance between the log and the bridge when the stone is released, for that first we need to find time taken by the stone to reach on top of log,

We have equation of motion. s = ut + 0.5 at²

       Initial velocity, u = 0 m/s

       Acceleration, a = 9.81 m/s²

       Displacement, s = 50.8 m

Substituting,

                  s = ut + 0.5 at²

                 50.8 = 0.5 x 9.81 x t²

                     t = 3.22 seconds,

So log travels 3.22 seconds at a speed of 5.36 m/s after the release of stone,

We have equation of motion. s = ut + 0.5 at²

       Initial velocity, u = 5.36 m/s

       Acceleration, a = 0 m/s²

       Time, t = 3.22 s

Substituting,

                  s = ut + 0.5 at²

                 s = 5.36 x 3.22 + 0.5 x 0 x 3.22²

                    s = 17.24 m

Horizontal distance between the log and the bridge when the stone is released = 17.24 m

3 0
3 years ago
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gayaneshka [121]

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5 0
2 years ago
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