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liberstina [14]
3 years ago
15

How do i solve thisx/12= 0​

Mathematics
2 answers:
Elis [28]3 years ago
7 0

Answer:

0

Step-by-step explanation:

0÷12=0

The way to figure this problem out is to multiply 0 by 12 and than you get 0.

MaRussiya [10]3 years ago
4 0

Anything divided or multiplied by 0=0 so x=0....0divided by 12=0

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$22.50

Step-by-step explanation:

First, you subtract 30 from 300 which is 270, then you divide 270 by 12 because there is 12 months in a year, and then you get 22.50 per month.

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Is the first number divisible by the second 790 by 2
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Da<br> A<br> Solve the equation 2x^2+3=0
Anika [276]

Answer:

x = ±i(√6 / 2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Solving quadratics

<u>Algebra II</u>

Imaginary root i

  • √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x² + 3 = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Subtract 3 on both sides:                        2x² = -3
  2. [Division Property of Equality] Divide 2 on both sides:                                  x² = -3/2
  3. [Equality Property] Square root both sides:                                                    x = ±√(-3/2)
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4 0
3 years ago
Find the slope of the tangent line to the curve f(x)=e^(x) at (0.4,1.49)
almond37 [142]

Answer:

1.49

Step-by-step explanation:

In order to find the slope of the tangent line to a given equation, and in a given point, we need to:

1. Find the first derivative of the given function.

2. Evaluate the first derivative function in the given point.

1. Let's find the first derivative of the given function:

The original function is f(x)=e^{x}

But remeber that the derivative of  e^{x} is  e^{x}

so, f'(x)=e^{x}

2. Let's evaluate the first derivative function in the given point

The given point is (0.4,1.49) so:

f'(x)=e^{x}

f'(0.4)=e^{0.4}

f'(x)=1.49

Notice that the calculated slope of the tangent line is equal to the y-coordinate of the given point because f'(x)=f(x). In conclusion, the slope of the tangent line is equal to 1.49.

8 0
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