Answer:
a) The 95% confidence interval to estimate the average fee for the population is between $11.65 and $12.79
b) $0.57
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so
Now, find the margin of error M as such
In which
is the standard deviation of the population and n is the size of the sample.
So the answer for b) is $0.57.
The lower end of the interval is the sample mean subtracted by M. So it is 12.22 - 0.57 = $11.65
The upper end of the interval is the sample mean added to M. So it is 12.22 + 0.57 = $12.79
The 95% confidence interval to estimate the average fee for the population is between $11.65 and $12.79
Answer:
Jaffrey will end up making $1214 in the first year
Step-by-step explanation:
950 + 12(22) = ?
first lets find out what 12 * 22 =?
12 * 22 = 264
now lets add 264 to 950
264 + 950 = 1214
<span>3^5 * 6^-6 / 3^3 * 6^-4
= 3^2 6^-2
= 3^2 / 6^2
= 9/36
=1/4
answer
</span><span>C.
1/4</span>
Answer:
![m = -\frac{4}{3}](https://tex.z-dn.net/?f=m%20%3D%20-%5Cfrac%7B4%7D%7B3%7D)
Step-by-step explanation:
![2m = -\frac{2}{3}](https://tex.z-dn.net/?f=2m%20%3D%20-%5Cfrac%7B2%7D%7B3%7D)
Divide both sides by 2 to get just m
![\frac{2m}{2} = \frac{-\frac{2}{3}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2m%7D%7B2%7D%20%3D%20%5Cfrac%7B-%5Cfrac%7B2%7D%7B3%7D%7D%7B2%7D)
You can't divide a fraction by a number so you do kcf (keep it, change it, flip it)
![m = -\frac{2}{3} x \frac{2}{1}](https://tex.z-dn.net/?f=m%20%3D%20-%5Cfrac%7B2%7D%7B3%7D%20x%20%5Cfrac%7B2%7D%7B1%7D)
![m = -\frac{4}{3}](https://tex.z-dn.net/?f=m%20%3D%20-%5Cfrac%7B4%7D%7B3%7D)
I think it’s the second one because The formula would be
x=
2a
−b±
b
2
−4ac