Question

Find the equation of the circle that has center (-1,1) and passes through (-5,6)

Answer 1

Answer:

I need more points sorry hope u get the answer:)

Step-by-step explanation:

Answer 2

Answer:

circle equation for each pair of points can be expressed as:

(x1−h)2+(y1−k)2=(x2−h)2+(y2−k)2,

we get : (x1−h)2−(x2−h)2=(y2−k)2−(y1−k)2,

(x1−x2)(x1+x2−2h)=(y2−y1)(y2+y1−2k)

Introducing a1=(x1−x2),a′1=(x1+x2),b1=(y2−y1),b′1=(y2+y1)