The expansion of the given expressions are; 4x² - 5x - 5; 2x² - 13x + 15; -2x² - 5x + 3; 3x² + 6x - 1
<h3>How to simplify Quadratic equations?</h3>
A) x(x - 5) + 3x² - 5
Expanding this gives us;
x² - 5x + 3x² - 5
⇒ 4x² - 5x - 5
B) (2x - 3)(x - 5)
Expanding the function gives;
⇒ (2x² - 3x - 10x + 15)
⇒ 2x² - 13x + 15
C) -2x(x + 3) + x + 3
⇒ -2x² - 6x + x + 3
⇒ -2x² - 5x + 3
D) 3(x + 1)² - 4
⇒ 3(x² + 2x + 1) - 4
⇒ 3x² + 6x + 3 - 4
⇒ 3x² + 6x - 1
Read more about Quadratic Equations at; brainly.com/question/1214333
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<span>rounded to 5 decimal places: 26287091.00000</span>
I think it might be pairs 2 & 3
Answer:
37044 different combinations of 4 movies can he rent if he wants at least one comedy
Step-by-step explanation:
The order in which the movies are selected is not important, so we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
How many different combinations of 4 movies can he rent if he wants at least one comedy
The easier way to solve this is subtract the total from the number of combinations with no comedies.
Total:
4 movies from a set of 14 + 19 = 33. So
No comedies:
4 movies from a set of 19.
At least one comedy:
40920 - 3876 = 37044
37044 different combinations of 4 movies can he rent if he wants at least one comedy
Sam makes sweeter coffee.