It is blank btw. Subject?
B.)155
a1+d(n-1)
a1+d(6-1)=50
a1+5d=50
a1+d(11-1)=85
a1+10d=85
a1=50-5d
(50-5d)+10d=85
50-5d+10d=85
5d+50=85
5d=35
d=7
a1+7(6-1)=50
a1+35=50
a1=15
15+7(n-1)
15+7(21-1)
15+7(20)
15+140=155
A set is simply the group of numbers.
- <em>The set of M and N are: </em><em> and </em><em>.</em>
- <em>The set of M n N is: </em><em>.</em>
- <em>The set of M u N is: </em><em />
<u>(a) The set of M and N</u>
Given that:
M = squares of integers less than 100
N = Positive odd numbers less than 15
So, we have:
<u>(b) M n N and M u N</u>
M n N is the set of common elements between sets M and N.
So, we have:
M u N is the set of all elements in sets M and N.
So, we have:
Read more about sets at:
brainly.com/question/2332158
4 is a solution to the equation. It is true.
Answer:
18
Step-by-step explanation:
.6*30
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