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aliya0001 [1]
2 years ago
9

I don’t know how to explain it.

Mathematics
1 answer:
DiKsa [7]2 years ago
4 0

\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt{x^6}\implies \sqrt[2]{x^6}\implies x^{\frac{6}{2}}\implies x^{\frac{3}{1}}\implies x^3

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Which equation gives the value of the circumference, CC, of a circle with a diameter of 5656 feet?
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5 0
2 years ago
A land owner is planning to build a fenced-in, rectangular patio behind his garage, using his garage as one of the "walls." He
Vitek1552 [10]

Answer:

Maximum area = 800 square feet.

Step-by-step explanation:

In the figure attached,

Rectangle is showing width = x ft and the side towards garage is not to be fenced.

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80 = x + x + y

80 = 2x + y

y = (80 - 2x)

Now area of the rectangle A = xy

Or function that represents the area of the rectangle is,

A(x) = x(80 - 2x)

A(x) = 80x - 2x²

To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.

A'(x)=\frac{d}{dx}(80x-2x^{2})

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A'(x) = 80 - 4x = 0

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x = \frac{80}{4}

x = 20

Therefore, for x = 20 ft area of the rectangular patio will be maximum.

A(20) = 80×(20) - 2×(20)²

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         = 800 square feet

Maximum area of the patio is 800 square feet.

7 0
3 years ago
A. 25'<br> B. 10'<br> C. 15'<br> D. 20'
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Answer:

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