Brian has 40000 to invest in a mix of corporate and municipal bonds. The corporate bond pays 10% simple annual interest and the
1 answer:
Answer:
Sum of money invested in corporate bonds = 30,000
Step-by-step explanation:
Total sum = 40,000
The rate of interest for corporate bonds = 10 % = 0.1
The rate of interest for municipal bonds = 6 % = 0.06
Total interest = 3600
Let sum of money invested in corporate bonds = x
The sum of money invested in municipal bonds = 40000 - x
× 0.1 × 1 + (
) × 0.06 × 1 = 3600
(0.1- 0.06) + 2400 = 3600
0.04 = 1200
= 30,000
Since x = sum of money invested in corporate bonds
So sum of money invested in corporate bonds = 30000
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Answer:
3a) The value of x = 56
3b) The measure of ∠ H T M = 90°
3c) The radius of the circle = 53
Step-by-step explanation:
3a) ∵ A F is a tangent to the circle O at point F
∵ Secant AH intersects circle O at point T
∴ (A F)² = (A T)(A H)
∴ 7( x + 7) = (21)² ⇒ ÷ 7
∴ x + 7 = 63
∴ x = 63 - 7 = 56
3b) ∵ HM is a diameter
∴ The measure of the arc HM = 180° ⇒ semi-circle
∵ ∠ H T M is inscribed angle subtended by the arc HM
∴ m ∠ H T M = half the measure of arc HM
∴ m ∠ H T M = 180° ÷ 2 = 90°
3c) ∵ Δ H T M is a right angle triangle at T
∴ (H M)² = (M T)² + (H T)² ⇒ Pythagorean theorem
∴ (H M)² = (90)² + (56)²
∴ (H M)² = 11236
∴ HM = = 106
∴ OM = 106 ÷ 2 = 53
∵ OM is the radius of the circle O
∴ The radius = 53