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Mrac [35]
3 years ago
15

Write the equation of a circle with center (4, -5) and radius = square root of 13

Mathematics
2 answers:
Sophie [7]3 years ago
5 0

Answer:

The required equation in standard form is (x-4)^2+(y+5)^2=13

Step-by-step explanation:

The equation of a circle with center (h,k) an radius, r units is given by the formula;

(x-h)^2+(y-k)^2=r^2

The given circle has center (4,-5) and radius r=\sqrt{13}.

We substitute these values into the formula to obtain;

(x-4)^2+(y--5)^2=(\sqrt{13})^2

We simplify to get;

(x-4)^2+(y+5)^2=13

Anon25 [30]3 years ago
3 0
<h2>Hello!</h2>

The answer is:

The equation of the given circle is:

(x-4)^{2}+(y+5)^{2}=13

<h2>Why?</h2>

The equation of a circle is given by the following equation:

(x-h)^{2} +(y-k)^{2}=r^{2}

We are given the center point (4,-5) and the radius.

So,

Where:

h=x=4\\k=y=-5\\r=\sqrt{13}

Then, substituting into the circle equation, we have:

(x-4)^{2} +(y-(-5))^{2}=(\sqrt{13})^{2}

(x-4)^{2} +(y-(-5))^{2}=(\sqrt{13})^{2}

Hence, the simplified equation of the circle is:

(x-4)^{2}+(y+5)^{2}=13

Have a nice day!

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