The length of the KN is 4.4
Step-by-step explanation:
We know from Pythagoras theorem  
In a right angle ΔLMN  
Base² + perpendicular² = hypotenuse
²
From the properties of triangle we also know that altitudes are ⊥ on the sides they fall.
 Hence ∠LKM = ∠NKM = 90
°
Given values-
LM=12
LK=10
Let KN be “s”
⇒LN= LK + KN
⇒LN= 10+x        eq 1
Coming to the Δ LKM
⇒LK²+MK²= LM²
⇒MK²= 12²-10²
⇒MK²= 44           eq 2
Now in Δ MKN
⇒MK²+ KN²= MN²
⇒44+s²= MN²       eq 3
In Δ LMN
⇒LM²+MN²= LN²
Using the values of MN² and LN² from the previous equations
⇒12² + 44+s²= (10+s)
²
⇒144+44+s²= 100+s²+20s
⇒188+s²= 100+s²+20s    cancelling the common term “s²”
⇒20s= 188-100
∴ s= 4.4
Hence the value of KN is 4.4  
 
        
             
        
        
        
So 20600=100%
in 2009=1.2% change from 100%
not specific whether percent change is up or down so solve fo r1.2%
d
find 1.2% of 100
percent means parts out of 1001.2%=1.2/100=0.12/10=0.012/1=0.012
'of' means multiply
20600 times 0.012=276.2
the change is 276.2
20600-276.2=20352.8
20600+276.2=20847.2
you must round down since you can't sell 0.2 or 0.8 of a car
the sold either 20,352 or 20,847 cars in 2009
        
             
        
        
        
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r =  = 0.03125 inch
 = 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
 = 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
 =3.14 * 0.000976563
 = 0.003066406
 = 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
 
        
                    
             
        
        
        
11/29 i believe. Cuz you add them all together and get 29 and then red and green added together is 11